A pair of chain propagation steps for the radical bromination of propane to give 1-bromopropane has to be written and Δ H 0 for propagation steps and overall reaction has to be calculated. Concept introduction: Halogenation of alkanes : The replacement of one or more hydrogen atoms by halogen. When alkanes is heated or irradiated with the light of specific wavelength, the alkyl halide are formed by radical chain reaction. Radical chain reaction: Initiation reaction: Chain propagation: Chain termination: Bond dissociation energy is a measure of bond strength in a chemical bond . It is a change in enthalpy of a homolysis reaction at absolute zero where a molecule is broken down into two free radicals.

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 8.5, Problem 8.4P

Interpretation Introduction

Interpretation:

A pair of chain propagation steps for the radical bromination of propane to give 1-bromopropane has to be written and ΔH0 for propagation steps and overall reaction has to be calculated.

Concept introduction:

Halogenation of alkanes: The replacement of one or more hydrogen atoms by halogen. When alkanes is heated or irradiated with the light of specific wavelength, the alkyl halide are formed by radical chain reaction.

Radical chain reaction:

Initiation reaction:

Chain propagation:

Chain termination:

Bond dissociation energy is a measure of bond strength in a chemical bond.

It is a change in enthalpy of a homolysis reaction at absolute zero where a molecule is broken down into two free radicals.

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MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10 Consider the following reaction: CH3OH(g) CO(g) + 2H2(g) (Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.) Part A Calculate AG for this reaction at 25 °C under the following conditions: PCH₂OH Pco PH2 0.815 atm = 0.140 atm 0.170 atm Express your answer in kilojoules to three significant figures. Ο ΑΣΦ AG = -150 Submit Previous Answers Request Answer □? kJ × Incorrect; Try Again; 2 attempts remaining Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship: AGrxn = AGrxn + RTInQ, AGxn+RTInQ, where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a is the reaction quotient. Provide Feedback Next >

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Answer 2

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 8.5, Problem 8.4P

Interpretation Introduction

Interpretation:

A pair of chain propagation steps for the radical bromination of propane to give 1-bromopropane has to be written and ΔH0 for propagation steps and overall reaction has to be calculated.

Concept introduction:

Halogenation of alkanes: The replacement of one or more hydrogen atoms by halogen. When alkanes is heated or irradiated with the light of specific wavelength, the alkyl halide are formed by radical chain reaction.

Radical chain reaction:

Initiation reaction:

Chain propagation:

Chain termination:

Bond dissociation energy is a measure of bond strength in a chemical bond.

It is a change in enthalpy of a homolysis reaction at absolute zero where a molecule is broken down into two free radicals.

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Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 8.5, Problem 8.4P

Interpretation Introduction

Interpretation:

A pair of chain propagation steps for the radical bromination of propane to give 1-bromopropane has to be written and ΔH0 for propagation steps and overall reaction has to be calculated.

Concept introduction:

Halogenation of alkanes: The replacement of one or more hydrogen atoms by halogen. When alkanes is heated or irradiated with the light of specific wavelength, the alkyl halide are formed by radical chain reaction.

Radical chain reaction:

Initiation reaction:

Chain propagation:

Chain termination:

Bond dissociation energy is a measure of bond strength in a chemical bond.

It is a change in enthalpy of a homolysis reaction at absolute zero where a molecule is broken down into two free radicals.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 8.5, Problem 8.4P

Interpretation Introduction