
The cryptogram decoding using encoded 2×2 matrix.

Answer to Problem 64E
The message is
CANCEL ORDERS SUE
Explanation of Solution
Given information:
5 2 25 11 −2 −7 −15 −15 32 14−8 −13 38 19 −19 37 16
Formula used:
Matrix multiplication is used.
Calculation:
We have to decode the following cryptogram:
5 2 25 11 -2 -7 -15 -15 32 14 -8 -13 38 19 -19 -19 37 16
Using the some unknown decoding matrix A−1=[abcd]
Dividing them into 1×2 matrices we get,
[52][2511][−2−7][−15−15][3214][−8−13][3819][−19−19][3716]
The last word of the message is _SUE.
So,
[−19−19]×A−1=[−19−19]×[abcd] =[−19a−19c−19b−19d]
The first two letters of the last word are _ &. S. So,
−19a−19c=0 a=−cAnd−19b−19d=19 b+d=−1
Also we have
[3716]×A−1=[3716]×[abcd] =[37a+16c37b+16d]
The last two letters of the last word are U &. E. So,
Using a=−c and b+d=−1 we get,
37a−16a=21 21a=21 a=1
Thus,
c=−1
And we get
37(−1−d)+16d=5−37−37d+16d=5 21d=−42 d=−2
Thus, b=1
Thus, we have
A−1=[11−1−2]
Now to get the uncoded row matrices,
Coded matrix Decoding matrix Uncoded Matrix
[52][11−1−2][31][2511][11−1−2][143][−2−7][11−1−2][512][−15−15][11−1−2][015][3214][11−1−2][184][−8−13][11−1−2][518][3819][11−1−2][190]
[−19−19][11−1−2][019][3716][11−1−2][215]
We get the following uncoded row matrices,
[31][143][512][015][184][518][190][019][215]
Splitting them we get,
3 1 14 3 5 12 0 15 18 4 5 18 19 0 0 19 21 5
When the numbers are converted to the alphabets they are assigned to we get the message
CANCEL ORDERS SUE
Conclusion:
When the numbers are converted to the alphabets they are assigned to we get the message
CANCEL ORDERS SUE
Chapter 8 Solutions
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