Explanation Given: f ( x ) = 2 x x + 1 , g ( x ) = 1 ; f ( x ) < g ( x ) . Calculation: 2 x x + 1 < 1 2 x x + 1 − 1 < 0 2 x − x − 1 x + 1 < 0 x − 1 x + 1 < 0 Making numerator and denominator equal to zero, we get x − 1 = 0 and x + 1 = 0 x = 1 , − 1 Boundary points are -1 and 1 We get intervals: <

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ISBN: 8220101539229

Author: Blitzer

Publisher: Pearson Education (US)

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When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Chapter 8.5, Problem 59E

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To calculate: All values of x that satisfy the required inequality f(x)=2xx+1, g(x)=1; f(x)<g(x).

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Chapter 8.5, Problem 58E

Chapter 8.5, Problem 60E

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Chapter 8 Solutions

EBK INTERMEDIATE ALGEBRA FOR COLLEGE ST

Ch. 8.1 - Check Point 1 Solve: . Ch. 8.1 - Prob. 2CP Ch. 8.1 - Prob. 3CP Ch. 8.1 - Prob. 4CP Ch. 8.1 - Prob. 5CP Ch. 8.1 - Prob. 6CP Ch. 8.1 - Prob. 7CP Ch. 8.1 - Prob. 8CP Ch. 8.1 - Prob. 9CP Ch. 8.1 - Prob. 10CP

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All values of x that satisfy the required inequality f ( x ) = 2 x x + 1 , g ( x ) = 1 ; f ( x ) < g ( x ) .

Solution Summary: The author explains how to calculate all values of x that satisfy the required inequality: (-1,1).

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To calculate: All values of x that satisfy the required inequality f(x)=2xx+1, g(x)=1; f(x)<g(x).

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Chapter 8 Solutions

All values of x that satisfy the required inequality f ( x ) = 2 x x + 1 , g ( x ) = 1 ; f ( x ) &lt; g ( x ) .

Solution Summary: The author explains how to calculate all values of x that satisfy the required inequality: (-1,1).

Concept explainers

Videos

To calculate: All values of x that satisfy the required inequality f(x)=2xx+1, g(x)=1; f(x)<g(x).

Want to see the full answer?

Chapter 8 Solutions

All values of x that satisfy the required inequality f ( x ) = 2 x x + 1 , g ( x ) = 1 ; f ( x ) < g ( x ) .