Explanation Given: If air resistance is neglected, a projectile on Earth shot straight upward with an initial velocity of 40 meters per second will be at a height s (in meters) given by the function, f ( x ) = − 4.9 x 2 + 40 x Here, x is the number of seconds elapsed after projection. Formula used: The x -coordinate of the vertex is − b 2 a for the general equation of the type a x 2 + b x . Thus, maxima of a quadratic function y = a x 2 + b x + c is at x = − b 2 a when a < 0 . Calculation: As the initial velocity u = 40 meters per sec. Height after x seconds will be f ( x ) = − 4.9 x 2 + 40 x . Compare the above with the general equation a x 2 + b x + c , then a = − 4.9 b = 40 The x -coordinate of the vertex is; − b 2 a = − 40 2 ( − 4

Mathematical Ideas (13th Edition) - Standalone book

13th Edition

ISBN: 9780321977076

Author: Charles D. Miller, Vern E. Heeren, John Hornsby, Christopher Heeren

Publisher: PEARSON

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Chapter 8.5, Problem 45E

To determine

To calculate: The seconds in which projectile reach its maximum height, and the maximum height if the height is given as a function of number of seconds(x) as f(x)=−4.9x2+40x.

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Chapter 8.5, Problem 44E

Chapter 8.5, Problem 46E

Chapter 8 Solutions

Mathematical Ideas (13th Edition) - Standalone book

Ch. 8.1 - Fill in each blank with the correct response. 1....Ch. 8.1 - Fill in each blank with the correct response. For...Ch. 8.1 - Prob. 3E Ch. 8.1 - Prob. 4E Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Locate the following points on the rectangular...Ch. 8.1 - Locate the following points on the rectangular...Ch. 8.1 - Prob. 9E Ch. 8.1 - Locate the following points on the rectangular...

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The seconds in which projectile reach its maximum height, and the maximum height if the height is given as a function of number of seconds( x ) as f ( x ) = − 4.9 x 2 + 40 x .

Solution Summary: The author calculates the seconds in which a projectile reach its maximum height, and the height after 4.1 seconds, using the x -coordinate of the vertex.

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To calculate: The seconds in which projectile reach its maximum height, and the maximum height if the height is given as a function of number of seconds(x) as f(x)=−4.9x2+40x.

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Chapter 8 Solutions