The mass of water produced in the given reaction should be calculated if the 50g of CH 3 OH undergoes reaction with excess oxygen and the percent yield of the reaction is 53 .2% . Concept introduction: Mole ratios between the reactants and products of a reaction are depends upon the coefficients of respective reactant in a balanced chemical equation. Balanced chemical equation of a reaction is written according to law of conservation of mass. Number of moles of a substance, from its given mass is, Number of moles = Given mass Molecular mass Number of grams of a substance from its number of moles is, Number of moles × Molecular mass in grams = Number of grams Percent yield of reaction is the ratio of mass of actual yield to the mass of theoretical yield and multiplied with hundred.

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Chapter 8.4, Problem 8.4.4SR

Interpretation Introduction

Interpretation:

The mass of water produced in the given reaction should be calculated if the 50g of CH3OH undergoes reaction with excess oxygen and the percent yield of the reaction is 53.2%.

Concept introduction:

Mole ratios between the reactants and products of a reaction are depends upon the coefficients of respective reactant in a balanced chemical equation.

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Number of moles of a substance, from its given mass is,
Number of moles = Given massMolecular mass

Number of grams of a substance from its number of moles is,
Number of moles × Molecular mass in grams = Number of grams

Percent yield of reaction is the ratio of mass of actual yield to the mass of theoretical yield and multiplied with hundred.

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