Given code: //Include the necessary header files #include <stdio.h> #include "csapp.h" //Define a main() int main() { //Initialize the variable x as 1 int x=1; //Check the condition if(fork()==0) //Print the statement printf("p1: x=%d\n", ++x); //Print the statement printf("p2: x=%d\n", --x); //Exit exit(0); } Explanation: The given code is used to print the output of the child and parent processes. In the given code, the main program initializes the variable “x” as “1”. The “if” condition check, function “fork()” is equal to zero. Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”. Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”. Exit from the program.

Question

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Answer 1

Question

Chapter 8.4, Problem 8.2PP

A.

Program Plan Intro

Given code:

//Include the necessary header files

#include <stdio.h>

#include "csapp.h"

//Define a main()

int main()

{

//Initialize the variable x as 1

int x=1;

//Check the condition

if(fork()==0)

//Print the statement

printf("p1: x=%d\n", ++x);

//Print the statement

printf("p2: x=%d\n", --x);

//Exit

exit(0);

}

Explanation:

The given code is used to print the output of the child and parent processes.

In the given code, the main program initializes the variable “x” as “1”.

The “if” condition check, function “fork()” is equal to zero.

Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”.

Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”.

Exit from the program.

B.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Expert Solution & Answer

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See solution

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(a) Assume that five generation units with third order cost function (F: (P) = A: P²³ + B; P; ² + C; P; +D;) are in the circuit. Write a computer program using any arbitrary programming language (MATLAB, C++, C#, Python,...) to calculate economic. load dispatch (ELD) using first order gradient method. Note that all parameters and variables should be defined inside the program (at first lines) such that units' characteristics and demand can be changed easily. Neglect grid losses.

(a) A ssume that five generation unıts with third order cost function (F, (P) = A; P+ B;P+C; P; + D;) are in the circuit. Write a computer program using any arbitrary programming language (MATLAB, C++, C#, Python,.) to calculate economic load dispatch (ELD) using first order gradient method. Note that all parameters and variables should be defined inside the program (at tirst limes) such that units' charactenistics and demand can be changed easily. Neglect grid losses. O using lambda - iteration method.

(7) Discrete structure: Please solve it on urgent basis: Question # 7: Show that at least ten of any 64 days chosen must fall on the same day of the week.

Answer 2

Question

Chapter 8.4, Problem 8.2PP

A.

Program Plan Intro

Given code:

//Include the necessary header files

#include <stdio.h>

#include "csapp.h"

//Define a main()

int main()

{

//Initialize the variable x as 1

int x=1;

//Check the condition

if(fork()==0)

//Print the statement

printf("p1: x=%d\n", ++x);

//Print the statement

printf("p2: x=%d\n", --x);

//Exit

exit(0);

}

Explanation:

The given code is used to print the output of the child and parent processes.

In the given code, the main program initializes the variable “x” as “1”.

The “if” condition check, function “fork()” is equal to zero.

Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”.

Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”.

Exit from the program.

B.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 8.4, Problem 8.2PP

A.

Program Plan Intro

Given code:

//Include the necessary header files

#include <stdio.h>

#include "csapp.h"

//Define a main()

int main()

{

//Initialize the variable x as 1

int x=1;

//Check the condition

if(fork()==0)

//Print the statement

printf("p1: x=%d\n", ++x);

//Print the statement

printf("p2: x=%d\n", --x);

//Exit

exit(0);

}

Explanation:

The given code is used to print the output of the child and parent processes.

In the given code, the main program initializes the variable “x” as “1”.

The “if” condition check, function “fork()” is equal to zero.

Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”.

Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”.

Exit from the program.

B.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 8.4, Problem 8.2PP

A.

Program Plan Intro

Given code:

//Include the necessary header files

#include <stdio.h>

#include "csapp.h"

//Define a main()

int main()

{

//Initialize the variable x as 1

int x=1;

//Check the condition

if(fork()==0)

//Print the statement

printf("p1: x=%d\n", ++x);

//Print the statement

printf("p2: x=%d\n", --x);

//Exit

exit(0);

}

Explanation:

The given code is used to print the output of the child and parent processes.

In the given code, the main program initializes the variable “x” as “1”.

The “if” condition check, function “fork()” is equal to zero.

Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”.

Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”.

Exit from the program.

B.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 8.4, Problem 8.2PP

A.

Program Plan Intro

Given code:

//Include the necessary header files

#include <stdio.h>

#include "csapp.h"

//Define a main()

int main()

{

//Initialize the variable x as 1

int x=1;

//Check the condition

if(fork()==0)

//Print the statement

printf("p1: x=%d\n", ++x);

//Print the statement

printf("p2: x=%d\n", --x);

//Exit

exit(0);

}

Explanation:

The given code is used to print the output of the child and parent processes.

In the given code, the main program initializes the variable “x” as “1”.

The “if” condition check, function “fork()” is equal to zero.

Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”.

Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”.

Exit from the program.

B.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Answer 6

Chapter 8.4, Problem 8.2PP

A.

Program Plan Intro

Given code:

//Include the necessary header files

#include <stdio.h>

#include "csapp.h"

//Define a main()

int main()

{

//Initialize the variable x as 1

int x=1;

//Check the condition

if(fork()==0)

//Print the statement

printf("p1: x=%d\n", ++x);

//Print the statement

printf("p2: x=%d\n", --x);

//Exit

exit(0);

}

Explanation:

The given code is used to print the output of the child and parent processes.

In the given code, the main program initializes the variable “x” as “1”.

The “if” condition check, function “fork()” is equal to zero.

Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”.

Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”.

Exit from the program.

Answer 7

Chapter 8.4, Problem 8.2PP

A.

Program Plan Intro

Given code:

//Include the necessary header files

#include <stdio.h>

#include "csapp.h"

//Define a main()

int main()

{

//Initialize the variable x as 1

int x=1;

//Check the condition

if(fork()==0)

//Print the statement

printf("p1: x=%d\n", ++x);

//Print the statement

printf("p2: x=%d\n", --x);

//Exit

exit(0);

}

Explanation:

The given code is used to print the output of the child and parent processes.

In the given code, the main program initializes the variable “x” as “1”.

The “if” condition check, function “fork()” is equal to zero.

Condition is true, print the value of “x” by incrementing “1”. So, the value of “x” becomes “2”.

Otherwise, print the value of “x” by decrementing “1”. So, the value of “x” becomes “1”.

Exit from the program.

Answer 8

B.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Answer 9

B.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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See solution

Answer 13

Ch. 8.2 - Prob. 8.1PP Ch. 8.4 - Prob. 8.2PP Ch. 8.4 - Prob. 8.3PP Ch. 8.4 - Prob. 8.4PP Ch. 8.4 - Practice Problem 8.5 (solution page 797) Write a...Ch. 8.4 - Practice Problem 8.6 (solution page 797) Write a...Ch. 8.5 - Practice Problem 8.7 (solution page 798) Write a...Ch. 8.5 - Prob. 8.8PP Ch. 8 - Prob. 8.9HW Ch. 8 - In this chapter, we have introduced some functions...

Solution Summary: The author explains that the given code is used to print the output of the child and parent processes.

Explanation of Solution

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...

Want to see the full answer?

Chapter 8 Solutions

Solution Summary: The author explains that the given code is used to print the output of the child and parent processes.

Explanation of Solution

Output of the parent process: P2: x = 0 Explanation: In the given code, the main program initializes the variable “x” as “1”. The parent process check the condition, if the function “fork()” is equal to zero...

Want to see the full answer?

Chapter 8 Solutions

Output of the parent process:

P2: x = 0

Explanation:

In the given code, the main program initializes the variable “x” as “1”.

The parent process check the condition, if the function “fork()” is equal to zero...