Explanation Formula used: Area of the rectangle : The area of the rectangle is A = l ⋅ w , where l is length of the rectangle and w is width of the rectangle. Area of the circle : Area of the circle is A = π r 2 , where r is radius of the circle and area of the semicircle is A = π r 2 2 . A decimal approximation for π is 3.14. Calculation: From the given figure, observe that the area of the given figure is the sum of the two semi-circles and the rectangle. Note that, the area of the semi-circle which lies at the left end and the right end in the figure will be the half of the area of a circle. Here, the radius of the semi-circle is 5 m. So, the diameter of the semicircle will be 10 m. Compute the area of the two semi-circles. Substitute r = 5m in A = 2 ⋅ ( π r 2 2 ) . A = 2 ⋅ ( π 2 ⋅ ( 5 m ) 2 ) = 2 ⋅ ( π 2 ⋅ 25 sq m ) = 25 π sq m Replace π with 3

Basic College Mathematics (6th Edition) (What's New in Developmental Math)

6th Edition

ISBN: 9780134840420

Author: Elayn Martin-Gay

Publisher: PEARSON

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Chapter 8.4, Problem 65E

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The area of the given figure.

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Chapter 8.4, Problem 64E

Chapter 8.4, Problem 66E

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Chapter 8 Solutions

Basic College Mathematics (6th Edition) (What's New in Developmental Math)

Ch. 8.1 - Prob. 1P Ch. 8.1 - Prob. 2P Ch. 8.1 - Classify each angle as acute, right, obtuse, or...Ch. 8.1 - Find the complement of a 29° angle. Ch. 8.1 - Find the supplement of a 67° angle. Ch. 8.1 - Prob. 6P Ch. 8.1 - Prob. 7P Ch. 8.1 - Prob. 8P Ch. 8.1 - Prob. 1VRV Ch. 8.1 - Prob. 2VRV

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