Explanation Given: The probability that any one of the ten lanes are busy is 0.8 . Approach: Write the expression to obtain the probability. P ( X = x ) = C ( n , x ) p x q n − x q = 1 − p Here, p is the probability of success and q is the probability of failure. n is the total number checkout lanes. C is the combination. Calculation: Calculate the most probable number of checkout lanes that are busy at any instant q = 1 − 0.8 = 0.2 Substitute 10 for n , 0.8 for p and 0.2 for q P ( X = x + 1 ) ≥ P ( X = x ) C ( 10 , x + 1 ) ( 0.8 ) x + 1 ( 0.2 ) 10 − x = C ( 10 , x ) ( 0.8 ) x ( 0.2 ) 10 − x 10 ! ( x + 1 ) ! × ( 9 − x ) ! ( 0 To determine (b) The probability that the number of checkout lines found in part ( a ) occurs.

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Author: Tan

Publisher: CENGAGE C

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Chapter 8.4, Problem 48E

To determine

(a)

The most probable number of checkout lanes that are busy at any instant.

To determine

(b)

The probability that the number of checkout lines found in part (a) occurs.

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Chapter 8.4, Problem 47E

Chapter 8.4, Problem 49E

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Ch. 8.1 - What is a random variable? Give an example.Ch. 8.1 - Prob. 2CQ Ch. 8.1 - Prob. 3CQ Ch. 8.1 - Three balls are selected at random without...Ch. 8.1 - 2.A coin is tossed four times. Let the random...Ch. 8.1 - A die is rolled repeatedly until a 6 falls...Ch. 8.1 - Cards are selected one at a time without...Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Prob. 7E

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(a) The most probable number of checkout lanes that are busy at any instant.

Solution Summary: The author explains how to determine the most probable number of checkout lanes that are busy at any instant.