Chapter 8.4, Problem 22STP

To determine

To find:The rate of change for the linear function.

Answer to Problem 22STP

The rate of change increase to 1.08 miles per minute.

Explanation of Solution

Given:

  

Calculation:

Consider the table that shows relationship between time and distance:

Time (minute) [x]	Distance (mi) [y]
30	32.5
45	48.75
60	65.0
75	81.25
90	97.5

The rate of change is change in one quality with respect to another quantity.

Mathematically:

  $Rateof\text{}\text{}\text{}\text{}change=\frac{change\text{}\text{}iny}{changeinx}$

Thus, the rate of change is change in distance with respect to change in time.

So,

  $\begin{array}{l}\text{Rate of change=}\frac{\text{48}\text{.75-32}\text{.5}}{\text{45-30}}\\ \text{=}\frac{\text{16}\text{.25}}{\text{15}}\text{=1}\text{.08333}\end{array}$

Conclusion:

Therefore, the rate of change increases to 1.08 miles per minute.