Explanation Given Information: The equation to be solved is r 4 − 8 r 2 = − 15 . Formula used: Steps to solve an equation in the quadratic form a u 2 + b u + c = 0 , a ≠ 0 where u is an algebraic expression. Step 1 : Substitute the variable of the equation with u to convert the equation in quadratic form a u 2 + b u + c = 0 where u is an algebraic expression. Step 2 : Solve the equation a u 2 + b u + c = 0 for u by factorizing. Step 3 : Replace u in the function with the original variable in step 1 . Step 4 : Now solve for the resulting equation for the original variable. Zero factor property states that if a b = 0 , then a = 0 or b = 0 . Calculation: Consider the equation r 4 − 8 r 2 = − 15 . Let u = r 2 . Therefore, u 2 = r 4 To convert the equation r 4 − 8 r 2 = − 15 in quadratic form a u 2 + b u + c = 0 , add 15 to both the sides, r 4 −

Intermediate Algebra For College Students (10th Edition)

10th Edition

ISBN: 9780134758992

Author: Allen R. Angel, Dennis Runde

Publisher: PEARSON

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Chapter 8.4, Problem 17ES

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To calculate: The solutions of the equation r4−8r2=−15 by converting it in the quadratic form au2+bu+c=0, a≠0 where u is an algebraic expression.

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Chapter 8.4, Problem 16ES

Chapter 8.4, Problem 18ES

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Chapter 8 Solutions

Intermediate Algebra For College Students (10th Edition)

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The solutions of the equation r 4 − 8 r 2 = − 15 by converting it in the quadratic form a u 2 + b u + c = 0 , a ≠ 0 where u is an algebraic expression.

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To calculate: The solutions of the equation r4−8r2=−15 by converting it in the quadratic form au2+bu+c=0, a≠0 where u is an algebraic expression.

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Chapter 8 Solutions