Explanation Given: The value mean and standard deviation is given as, μ X = 50 σ X = 1.4 Approach: Chebychev’s inequality, Assume X be a random variable with mean μ and standard deviation σ , then the probability of chosen outcome lies between μ − k σ and μ + k σ is at least 1 − 1 k 2 , where k is the number of standard deviation from mean: P ( μ − k σ ≤ X ≤ μ + k σ ) ≥ 1 − 1 k 2 Calculation: The value of k can be determined by lower bound or upper bound, By lower bound. μ − k σ = 50 − c ( 50 ) − k ( 1.4 ) = 50 − c k = c 1.4 By upper bound,

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Chapter 8.3, Problem 43E

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The value of $c$ by using Chebychev’s inequality,

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Chapter 8.3, Problem 42E

Chapter 8.3, Problem 44E

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Ch. 8.1 - What is a random variable? Give an example.Ch. 8.1 - Prob. 2CQ Ch. 8.1 - Prob. 3CQ Ch. 8.1 - Three balls are selected at random without...Ch. 8.1 - 2.A coin is tossed four times. Let the random...Ch. 8.1 - A die is rolled repeatedly until a 6 falls...Ch. 8.1 - Cards are selected one at a time without...Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Prob. 7E

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