Chapter 8.3, Problem 1ACYP

To determine

To calculate:To find four solutions for the below equation and to write the solutions as ordered pair −

  $y=x+2$

Answer to Problem 1ACYP

The four solutions as ordered pairs are $\left(0,2\right)$ , $\left(1,3\right)$ , $\left(2,4\right)$ and $\left(3,5\right)$ .

Explanation of Solution

Given information:

Equation is $y=x+2$

Formula Used:

To solve an equation with multiple variables, we need to consider some random values for one of the variables and solve for the other one to find the ordered pair.

Calculation:

Given equation is $y=x+2$

Using the above explanation, we have -

Let the value of $x$ be $0$ , substituting the value of $x$ in the above equation, we have:

  $y=0+2$

Solving the above equation, we have :

  $y=2$

Thus, the first ordered pair is $\left(0,2\right)$ .

Using the same approach to find the other ordered pairs −

Let the value of $x$ be $1$ , substituting the value of $x$ in the above equation, we have:

  $y=1+2$

Solving the above equation, we have :

  $y=3$

Thus, the second ordered pair is $\left(1,3\right)$ .

Let the value of $x$ be $2$ , substituting the value of $x$ in the above equation, we have:

  $y=2+2$

Solving the above equation, we have :

  $y=4$

Thus, the third ordered pair is $\left(2,4\right)$ .

Let the value of $x$ be $3$ , substituting the value of $x$ in the above equation, we have:

  $y=3+2$

Solving the above equation, we have :

  $y=5$

Thus, the fourth ordered pair is $\left(3,5\right)$ .

Thus, the four ordered pairs are $\left(0,2\right)$ , $\left(1,3\right)$ , $\left(2,4\right)$ and $\left(3,5\right)$ .