Essential Statistics
2nd Edition
ISBN: 9781259570643
Author: Navidi
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 8.3, Problem 12E
a.
To determine
Find the P-value.
b.
To determine
Find the P-value.
c.
To determine
Find the P-value.
d.
To determine
Find the P-value.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
What is one sample T-test? Give an example of business application of this test?
What is Two-Sample T-Test. Give an example of business application of this test?
.What is paired T-test. Give an example of business application of this test?
What is one way ANOVA test. Give an example of business application of this test?
1. One Sample T-Test: Determine whether the average satisfaction rating of customers for a product is significantly different from a hypothetical mean of 75.
(Hints: The null can be about maintaining status-quo or no difference; If your alternative hypothesis is non-directional (e.g., μ≠75), you should use the two-tailed p-value from excel file to make a decision about rejecting or not rejecting null. If alternative is directional (e.g., μ < 75), you should use the lower-tailed p-value. For alternative hypothesis μ > 75, you should use the upper-tailed p-value.)
H0 =
H1=
Conclusion: The p value from one sample t-test is _______. Since the two-tailed p-value…
Using the accompanying Accounting Professionals data to answer the following questions.
a. Find and interpret a 90% confidence interval for the mean years of service.
b. Find and interpret a 90% confidence interval for the proportion of employees who have a graduate degree.
view the Accounting Professionals data.
Employee Years of Service Graduate Degree?1 26 Y2 8 N3 10 N4 6 N5 23 N6 5 N7 8 Y8 5 N9 26 N10 14 Y11 10 N12 8 Y13 7 Y14 27 N15 16 Y16 17 N17 21 N18 9 Y19 9 N20 9 N
Question content area bottom
Part 1
a. A 90% confidence interval for the mean years of service is
(Use ascending order. Round to two decimal places as needed.)
If, based on a sample size of 900,a political candidate finds that 509people would vote for him in a two-person race, what is the 95%confidence interval for his expected proportion of the vote? Would he be confident of winning based on this poll?
Question content area bottom
Part 1
A
9595%
confidence interval for his expected proportion of the vote is
(Use ascending order. Round to four decimal places as needed.)
Chapter 8 Solutions
Essential Statistics
Ch. 8.1 - Check Your Understanding
1. Last year, the mean...Ch. 8.1 - Prob. 2CYUCh. 8.1 - Prob. 3CYUCh. 8.1 - Prob. 4CYUCh. 8.1 - Prob. 5CYUCh. 8.1 - Prob. 6CYUCh. 8.1 - Prob. 7ECh. 8.1 - Prob. 8ECh. 8.1 - Prob. 9ECh. 8.1 - In Exercises 9–12, determine whether the statement...
Ch. 8.1 - In Exercises 9–12, determine whether the statement...Ch. 8.1 - In Exercises 9–12, determine whether the statement...Ch. 8.1 - Prob. 13ECh. 8.1 - Practicing the Skills
In Exercises 13–16,...Ch. 8.1 - Prob. 15ECh. 8.1 - Practicing the Skills
In Exercises 13–16,...Ch. 8.1 - Prob. 17ECh. 8.1 - Prob. 18ECh. 8.1 - Prob. 19ECh. 8.1 - Prob. 20ECh. 8.1 - Working with the Concepts
21. Fertilizer: A new...Ch. 8.1 - 22. Big fish: A sample of 100 flounder of a...Ch. 8.1 - Prob. 23ECh. 8.1 - 24. Coffee: The mean caffeine content per cup of...Ch. 8.1 - Prob. 25ECh. 8.1 - Prob. 26ECh. 8.1 - 27. Type I error: A company that manufactures...Ch. 8.1 - Prob. 28ECh. 8.1 - Prob. 29ECh. 8.1 - Prob. 30ECh. 8.2 - Prob. 1CYUCh. 8.2 - Prob. 2CYUCh. 8.2 - Prob. 3CYUCh. 8.2 - Prob. 4CYUCh. 8.2 - Prob. 5CYUCh. 8.2 - Prob. 6CYUCh. 8.2 - Prob. 7CYUCh. 8.2 - Prob. 8CYUCh. 8.2 - Prob. 9CYUCh. 8.2 - Prob. 10CYUCh. 8.2 - Prob. 11CYUCh. 8.2 - Prob. 12CYUCh. 8.2 - 13. For each of the following P-values, state...Ch. 8.2 - Prob. 14CYUCh. 8.2 - Prob. 15CYUCh. 8.2 - Prob. 16CYUCh. 8.2 - Prob. 17CYUCh. 8.2 - Prob. 18CYUCh. 8.2 - Prob. 19CYUCh. 8.2 - Prob. 20CYUCh. 8.2 - Prob. 21CYUCh. 8.2 - A certain type of calculator battery has a mean...Ch. 8.2 - Prob. 23ECh. 8.2 - Prob. 24ECh. 8.2 - Prob. 25ECh. 8.2 - Prob. 26ECh. 8.2 - Prob. 27ECh. 8.2 - Prob. 28ECh. 8.2 - Prob. 29ECh. 8.2 - Prob. 30ECh. 8.2 - Prob. 31ECh. 8.2 - Prob. 32ECh. 8.2 - Prob. 33ECh. 8.2 - In Exercises 29–34, determine whether the...Ch. 8.2 - Prob. 35ECh. 8.2 - Prob. 36ECh. 8.2 - Prob. 37ECh. 8.2 - Prob. 38ECh. 8.2 - Prob. 39ECh. 8.2 - Prob. 40ECh. 8.2 - Prob. 41ECh. 8.2 - Prob. 42ECh. 8.2 - Prob. 43ECh. 8.2 - Prob. 44ECh. 8.2 - Prob. 45ECh. 8.2 - Prob. 46ECh. 8.2 - Prob. 47ECh. 8.2 - Prob. 48ECh. 8.2 - Prob. 49ECh. 8.2 - Prob. 50ECh. 8.2 - Prob. 51ECh. 8.2 - Prob. 52ECh. 8.2 - Prob. 53ECh. 8.2 - Prob. 54ECh. 8.2 - Prob. 55ECh. 8.2 - Prob. 56ECh. 8.2 - Prob. 57ECh. 8.2 - Prob. 58ECh. 8.2 - Prob. 59ECh. 8.2 - Prob. 60ECh. 8.2 - Prob. 61ECh. 8.2 - Prob. 62ECh. 8.2 - Prob. 63ECh. 8.2 - Prob. 64ECh. 8.2 - Prob. 65ECh. 8.2 - Prob. 66ECh. 8.2 - Prob. 67ECh. 8.2 - Prob. 68ECh. 8.2 - Prob. 69ECh. 8.2 - Prob. 70ECh. 8.2 - Prob. 71ECh. 8.2 - Prob. 72ECh. 8.3 - Prob. 1CYUCh. 8.3 - Prob. 2CYUCh. 8.3 - Prob. 3CYUCh. 8.3 - Prob. 4CYUCh. 8.3 - Prob. 5CYUCh. 8.3 - Prob. 6CYUCh. 8.3 - Prob. 7ECh. 8.3 - In Exercises 7 and 8, fill in each blank with the...Ch. 8.3 - Prob. 9ECh. 8.3 - Prob. 10ECh. 8.3 - Prob. 11ECh. 8.3 - Prob. 12ECh. 8.3 - Prob. 13ECh. 8.3 - Prob. 14ECh. 8.3 - Prob. 15ECh. 8.3 - Prob. 16ECh. 8.3 - Prob. 17ECh. 8.3 - Prob. 18ECh. 8.3 - Prob. 19ECh. 8.3 - Prob. 20ECh. 8.3 - Prob. 21ECh. 8.3 - How much is in that can? A machine that fills...Ch. 8.3 - Credit card debt: Following arc outstanding credit...Ch. 8.3 - Prob. 24ECh. 8.3 - Prob. 25ECh. 8.3 - Prob. 26ECh. 8.3 - Prob. 27ECh. 8.3 - Prob. 28ECh. 8.3 - Prob. 29ECh. 8.3 - Prob. 30ECh. 8.3 - Prob. 31ECh. 8.3 - Prob. 32ECh. 8.3 - Prob. 33ECh. 8.3 - Prob. 34ECh. 8.3 - Prob. 35ECh. 8.3 - Prob. 36ECh. 8.3 - Prob. 37ECh. 8.3 - Prob. 38ECh. 8.3 - Prob. 39ECh. 8.3 - Prob. 40ECh. 8.3 - Prob. 41ECh. 8.4 - Prob. 1CYUCh. 8.4 - Prob. 2CYUCh. 8.4 - Prob. 3CYUCh. 8.4 - A Gallup poll taken in December 2009 sampled 1000...Ch. 8.4 - Prob. 5ECh. 8.4 - Prob. 6ECh. 8.4 - Prob. 7ECh. 8.4 - In Exercises 7 and 8, determine whether the...Ch. 8.4 - Prob. 9ECh. 8.4 - Prob. 10ECh. 8.4 - Prob. 11ECh. 8.4 - Prob. 12ECh. 8.4 - Prob. 13ECh. 8.4 - Prob. 14ECh. 8.4 - Prob. 15ECh. 8.4 - Prob. 16ECh. 8.4 - Prob. 17ECh. 8.4 - Prob. 18ECh. 8.4 - Prob. 19ECh. 8.4 - Prob. 20ECh. 8.4 - Prob. 21ECh. 8.4 - Prob. 22ECh. 8.4 - Prob. 23ECh. 8.4 - Prob. 24ECh. 8.4 - Prob. 25ECh. 8.4 - Interpret calculator display: The following...Ch. 8.4 - Prob. 27ECh. 8.4 - Prob. 28ECh. 8.4 - Prob. 29ECh. 8.4 - Who will you vote for? A simple random sample of...Ch. 8.4 - Prob. 31ECh. 8.4 - Prob. 32ECh. 8.4 - Prob. 33ECh. 8.5 - Prob. 1CYUCh. 8.5 - Prob. 2CYUCh. 8.5 - Prob. 3CYUCh. 8.5 - Prob. 4CYUCh. 8.5 - Prob. 5ECh. 8.5 - Prob. 6ECh. 8.5 - Prob. 7ECh. 8.5 - Prob. 8ECh. 8.5 - Prob. 9ECh. 8.5 - Prob. 10ECh. 8.5 - Prob. 11ECh. 8.5 - Prob. 12ECh. 8.5 - Prob. 13ECh. 8.5 - Prob. 14ECh. 8.5 - Mercury pollution: Mercury is a toxic metal that...Ch. 8.5 - Ladies’ shoes: A random sample of 100 pairs of...Ch. 8 - Prob. 1CQCh. 8 - Prob. 2CQCh. 8 - Prob. 3CQCh. 8 - Prob. 4CQCh. 8 - Prob. 5CQCh. 8 - Prob. 6CQCh. 8 - Prob. 7CQCh. 8 - Prob. 8CQCh. 8 - Prob. 9CQCh. 8 - Prob. 10CQCh. 8 - Prob. 11CQCh. 8 - Prob. 12CQCh. 8 - Prob. 13CQCh. 8 - Prob. 14CQCh. 8 - Prob. 15CQCh. 8 - Prob. 1RECh. 8 - Prob. 2RECh. 8 - Prob. 3RECh. 8 - Prob. 4RECh. 8 - Prob. 5RECh. 8 - Prob. 6RECh. 8 - Prob. 7RECh. 8 - Prob. 8RECh. 8 - Prob. 9RECh. 8 - Prob. 10RECh. 8 - Interpret calculator display: The following TI-84...Ch. 8 - Prob. 12RECh. 8 - Prob. 13RECh. 8 - Prob. 14RECh. 8 - Prob. 15RECh. 8 - Prob. 1WAICh. 8 - What does the P-value represent?
Ch. 8 - Prob. 3WAICh. 8 - Prob. 4WAICh. 8 - Prob. 5WAICh. 8 - Prob. 1CSCh. 8 - Prob. 2CSCh. 8 - Prob. 3CSCh. 8 - Prob. 4CSCh. 8 - Prob. 5CSCh. 8 - Prob. 6CSCh. 8 - Prob. 7CS
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- Questions An insurance company's cumulative incurred claims for the last 5 accident years are given in the following table: Development Year Accident Year 0 2018 1 2 3 4 245 267 274 289 292 2019 255 276 288 294 2020 265 283 292 2021 263 278 2022 271 It can be assumed that claims are fully run off after 4 years. The premiums received for each year are: Accident Year Premium 2018 306 2019 312 2020 318 2021 326 2022 330 You do not need to make any allowance for inflation. 1. (a) Calculate the reserve at the end of 2022 using the basic chain ladder method. (b) Calculate the reserve at the end of 2022 using the Bornhuetter-Ferguson method. 2. Comment on the differences in the reserves produced by the methods in Part 1.arrow_forwardA population that is uniformly distributed between a=0and b=10 is given in sample sizes 50( ), 100( ), 250( ), and 500( ). Find the sample mean and the sample standard deviations for the given data. Compare your results to the average of means for a sample of size 10, and use the empirical rules to analyze the sampling error. For each sample, also find the standard error of the mean using formula given below. Standard Error of the Mean =sigma/Root Complete the following table with the results from the sampling experiment. (Round to four decimal places as needed.) Sample Size Average of 8 Sample Means Standard Deviation of 8 Sample Means Standard Error 50 100 250 500arrow_forwardA survey of 250250 young professionals found that two dash thirdstwo-thirds of them use their cell phones primarily for e-mail. Can you conclude statistically that the population proportion who use cell phones primarily for e-mail is less than 0.720.72? Use a 95% confidence interval. Question content area bottom Part 1 The 95% confidence interval is left bracket nothing comma nothing right bracket0.60820.6082, 0.72510.7251. As 0.720.72 is within the limits of the confidence interval, we cannot conclude that the population proportion is less than 0.720.72. (Use ascending order. Round to four decimal places as needed.)arrow_forward
- I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardA survey of 250 young professionals found that two-thirds of them use their cell phones primarily for e-mail. Can you conclude statistically that the population proportion who use cell phones primarily for e-mail is less than 0.72? Use a 95% confidence interval. Question content area bottom Part 1 The 95% confidence interval is [ ], [ ] As 0.72 is ▼ above the upper limit within the limits below the lower limit of the confidence interval, we ▼ can cannot conclude that the population proportion is less than 0.72. (Use ascending order. Round to four decimal places as needed.)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forward
- I need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardI need help with this problem and an explanation of the solution for the image described below. (Statistics: Engineering Probabilities)arrow_forwardQuestions An insurance company's cumulative incurred claims for the last 5 accident years are given in the following table: Development Year Accident Year 0 2018 1 2 3 4 245 267 274 289 292 2019 255 276 288 294 2020 265 283 292 2021 263 278 2022 271 It can be assumed that claims are fully run off after 4 years. The premiums received for each year are: Accident Year Premium 2018 306 2019 312 2020 318 2021 326 2022 330 You do not need to make any allowance for inflation. 1. (a) Calculate the reserve at the end of 2022 using the basic chain ladder method. (b) Calculate the reserve at the end of 2022 using the Bornhuetter-Ferguson method. 2. Comment on the differences in the reserves produced by the methods in Part 1.arrow_forward
- Questions An insurance company's cumulative incurred claims for the last 5 accident years are given in the following table: Development Year Accident Year 0 2018 1 2 3 4 245 267 274 289 292 2019 255 276 288 294 2020 265 283 292 2021 263 278 2022 271 It can be assumed that claims are fully run off after 4 years. The premiums received for each year are: Accident Year Premium 2018 306 2019 312 2020 318 2021 326 2022 330 You do not need to make any allowance for inflation. 1. (a) Calculate the reserve at the end of 2022 using the basic chain ladder method. (b) Calculate the reserve at the end of 2022 using the Bornhuetter-Ferguson method. 2. Comment on the differences in the reserves produced by the methods in Part 1.arrow_forwardFrom a sample of 26 graduate students, the mean number of months of work experience prior to entering an MBA program was 34.67. The national standard deviation is known to be18 months. What is a 90% confidence interval for the population mean? Question content area bottom Part 1 A 9090% confidence interval for the population mean is left bracket nothing comma nothing right bracketenter your response here,enter your response here. (Use ascending order. Round to two decimal places as needed.)arrow_forwardA test consists of 10 questions made of 5 answers with only one correct answer. To pass the test, a student must answer at least 8 questions correctly. (a) If a student guesses on each question, what is the probability that the student passes the test? (b) Find the mean and standard deviation of the number of correct answers. (c) Is it unusual for a student to pass the test by guessing? Explain.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Hypothesis Testing using Confidence Interval Approach; Author: BUM2413 Applied Statistics UMP;https://www.youtube.com/watch?v=Hq1l3e9pLyY;License: Standard YouTube License, CC-BY
Hypothesis Testing - Difference of Two Means - Student's -Distribution & Normal Distribution; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=UcZwyzwWU7o;License: Standard Youtube License