A tank of oxygen holds 20.0 L of oxygen ( O 2 ) at a pressure of 15.0 a t m . Calculate the volume, in litres, of this gas when it is released at a pressure of 1.00 a t m with no change in temperature and amount of gas Concept Introduction: Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept. According to the ideal gas equation: P V = n R T Where, P = P r e s s u r e o f I d e a l G a s V = V o l u m e o f G a s n = N u m b e r o f m o l e s o f g a s R = G a s C o n s t a n t T = T e m p e r a t e i n K e l v i n From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

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Answer 1

Question

Chapter 8.2, Problem 8.20QAP

Interpretation Introduction

Interpretation: A tank of oxygen holds $20.0 L$ of oxygen ( $O_{2}$ ) at a pressure of $15.0 a t m$ . Calculate the volume, in litres, of this gas when it is released at a pressure of $1.00 a t m$ with no change in temperature and amount of gas

Concept Introduction:

Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept.

According to the ideal gas equation:

$P V = n R T$

Where, $P = P r e s s u r e o f I d e a l G a s$

$V = V o l u m e o f G a s$

$n = N u m b e r o f m o l e s o f g a s$

$R = G a s C o n s t a n t$

$T = T e m p e r a t e i n K e l v i n$

From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

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Answer 2

Question

Chapter 8.2, Problem 8.20QAP

Interpretation Introduction

Interpretation: A tank of oxygen holds $20.0 L$ of oxygen ( $O_{2}$ ) at a pressure of $15.0 a t m$ . Calculate the volume, in litres, of this gas when it is released at a pressure of $1.00 a t m$ with no change in temperature and amount of gas

Concept Introduction:

Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept.

According to the ideal gas equation:

$P V = n R T$

Where, $P = P r e s s u r e o f I d e a l G a s$

$V = V o l u m e o f G a s$

$n = N u m b e r o f m o l e s o f g a s$

$R = G a s C o n s t a n t$

$T = T e m p e r a t e i n K e l v i n$

From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 8.2, Problem 8.20QAP

Interpretation Introduction

Interpretation: A tank of oxygen holds $20.0 L$ of oxygen ( $O_{2}$ ) at a pressure of $15.0 a t m$ . Calculate the volume, in litres, of this gas when it is released at a pressure of $1.00 a t m$ with no change in temperature and amount of gas

Concept Introduction:

Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept.

According to the ideal gas equation:

$P V = n R T$

Where, $P = P r e s s u r e o f I d e a l G a s$

$V = V o l u m e o f G a s$

$n = N u m b e r o f m o l e s o f g a s$

$R = G a s C o n s t a n t$

$T = T e m p e r a t e i n K e l v i n$

From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 8.2, Problem 8.20QAP

Interpretation Introduction

Interpretation: A tank of oxygen holds $20.0 L$ of oxygen ( $O_{2}$ ) at a pressure of $15.0 a t m$ . Calculate the volume, in litres, of this gas when it is released at a pressure of $1.00 a t m$ with no change in temperature and amount of gas

Concept Introduction:

Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept.

According to the ideal gas equation:

$P V = n R T$

Where, $P = P r e s s u r e o f I d e a l G a s$

$V = V o l u m e o f G a s$

$n = N u m b e r o f m o l e s o f g a s$

$R = G a s C o n s t a n t$

$T = T e m p e r a t e i n K e l v i n$

From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 8.2, Problem 8.20QAP

Interpretation Introduction

Interpretation: A tank of oxygen holds $20.0 L$ of oxygen ( $O_{2}$ ) at a pressure of $15.0 a t m$ . Calculate the volume, in litres, of this gas when it is released at a pressure of $1.00 a t m$ with no change in temperature and amount of gas

Concept Introduction:

Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept.

According to the ideal gas equation:

$P V = n R T$

Where, $P = P r e s s u r e o f I d e a l G a s$

$V = V o l u m e o f G a s$

$n = N u m b e r o f m o l e s o f g a s$

$R = G a s C o n s t a n t$

$T = T e m p e r a t e i n K e l v i n$

From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

Answer 6

Chapter 8.2, Problem 8.20QAP

Interpretation Introduction

Interpretation: A tank of oxygen holds $20.0 L$ of oxygen ( $O_{2}$ ) at a pressure of $15.0 a t m$ . Calculate the volume, in litres, of this gas when it is released at a pressure of $1.00 a t m$ with no change in temperature and amount of gas

Concept Introduction:

Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept.

According to the ideal gas equation:

$P V = n R T$

Where, $P = P r e s s u r e o f I d e a l G a s$

$V = V o l u m e o f G a s$

$n = N u m b e r o f m o l e s o f g a s$

$R = G a s C o n s t a n t$

$T = T e m p e r a t e i n K e l v i n$

From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

Answer 7

Chapter 8.2, Problem 8.20QAP

Interpretation Introduction

Interpretation: A tank of oxygen holds $20.0 L$ of oxygen ( $O_{2}$ ) at a pressure of $15.0 a t m$ . Calculate the volume, in litres, of this gas when it is released at a pressure of $1.00 a t m$ with no change in temperature and amount of gas

Concept Introduction:

Pressure is caused by the rapid motion of the molecules of the substance, particularly gas, with the walls of the container in which the gas is kept.

According to the ideal gas equation:

$P V = n R T$

Where, $P = P r e s s u r e o f I d e a l G a s$

$V = V o l u m e o f G a s$

$n = N u m b e r o f m o l e s o f g a s$

$R = G a s C o n s t a n t$

$T = T e m p e r a t e i n K e l v i n$

From the above equation, we get that Pressure is inversely proportional to the Volume. Thus, if pressure increases, then volume decreases and vice versa.

Answer 8

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