(a)
Interpretation:
The element with its full and condensed electron configuration and the number of inner electrons is to be determined from the given partial orbital diagram.
Concept introduction:
The electronic configuration tells about the distribution of electrons in various atomic orbitals.
The full electronic configuration of an atom tells about the distribution of electrons in its various atomic orbital.
The condensed electronic configuration is a way to write the electronic configuration where the inner shell configurations are compressed to the nearest noble gas configuration and only the valence shell configuration is written in the expanded form.
The partial orbital diagram is the one that shows the distribution of valence electrons only.
The inner electrons are present in the inner orbitals of the atom and the valence electrons are present in the outermost shell of the atom.
The number of inner electrons is calculated by subtracting the valence electrons from the total number of electrons
(b)
Interpretation:
The element with its full and condensed electron configuration and the number of inner electrons is to be determined from the given partial orbital diagram.
Concept introduction:
The electronic configuration tells about the distribution of electrons in various atomic orbitals.
The full electronic configuration of an atom tells about the distribution of electrons in its various atomic orbital.
The condensed electronic configuration is a way to write the electronic configuration where the inner shell configurations are compressed to the nearest noble gas configuration and only the valence shell configuration is written in the expanded form.
The partial orbital diagram is the one that shows the distribution of valence electrons only.
The inner electrons are present in the inner orbitals of the atom and the valence electrons are present in the outermost shell of the atom.
The number of inner electrons is calculated by subtracting the valence electrons from the total number of electrons
(c)
Interpretation:
The element with its full and condensed electron configuration and the number of inner electrons is to be determined from the given partial orbital diagram.
Concept introduction:
The electronic configuration tells about the distribution of electrons in various atomic orbitals.
The full electronic configuration of an atom tells about the distribution of electrons in its various atomic orbital.
The condensed electronic configuration is a way to write the electronic configuration where the inner shell configurations are compressed to the nearest noble gas configuration and only the valence shell configuration is written in the expanded form.
The partial orbital diagram is the one that shows the distribution of valence electrons only.
The inner electrons are present in the inner orbitals of the atom and the valence electrons are present in the outermost shell of the atom.
The number of inner electrons is calculated by subtracting the valence electrons from the total number of electrons
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Chapter 8 Solutions
CHEMISTRY:MOLECULAR...(LL) W/ALEKS
- Nonearrow_forward3. A molecular form of "dicarbon", C2, can be generated in gas phase. Its bond dissociation energy has been determined at 599 kJ/mol. Use molecular orbital theory to explain why energy of dissociation for C₂+ is 513 kJ/mol, and that for C2² is 818 kJ/mol. (10 points)arrow_forward9.73 g of lead(IV) chloride contains enough Cl- ions to make ____ g of magnesium chloride.arrow_forward
- 6. a) C2's. Phosphorus pentafluoride PF5 belongs to D3h symmetry group. Draw the structure of the molecule, identify principal axis of rotation and perpendicular (4 points) b) assume that the principal axis of rotation is aligned with z axis, assign symmetry labels (such as a1, b2, etc.) to the following atomic orbitals of the P atom. (character table for this group is included in the Supplemental material). 3s 3pz (6 points) 3dz²arrow_forward2. Construct Lewis-dot structures, and draw VESPR models for the ions listed below. a) SiF5 (4 points) b) IOF4 (4 points)arrow_forward5. Complex anion [AuCl2]¯ belongs to Doh symmetry point group. What is the shape of this ion? (4 points)arrow_forward
- 4. Assign the following molecules to proper point groups: Pyridine N 1,3,5-triazine N Narrow_forward7. a) Under normal conditions (room temperature & atmospheric pressure) potassium assumes bcc lattice. Atomic radius for 12-coordinate K atom is listed as 235 pm. What is the radius of potassium atom under normal conditions? (3 points) b) Titanium metal crystallyzes in hcp lattice. Under proper conditions nitrogen can be absorbed into the lattice of titanium resulting in an alloy of stoichiometry TiNo.2. Is this compound likely to be a substitutional or an interstitial alloy? (Radius of Ti (12-coordinate) is 147 pm; radius of N atom is 75 pm. (3 points)arrow_forwardcan someone answer the questions and draw out the complete mechanismarrow_forward
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