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Single Variable Calculus: Early Transcendentals, Books a la Carte, and MyLab Math with Pearson eText -- Title-Specific Access Card Package (3rd Edition)
- By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form x2+y2+Dx+Ey+F=0, we see that D=2h,E=2k, and F=h2+k2r2. Therefore, the center and the length of a radius of a circle can be found by using h=D2,k=E2 and r=h2+k2F. Use these relationship to find the center and the length of the radius of each of the following circles. x2+y2+4x14y+49=0arrow_forwardMultiple Choice (Choose the best answer): For the integral f sin³ x cos³ x dx, a. The substitution u = sin x will work, but u = cos x will not. b. The substitution u = cos x will work, but u = sin x will not. c. Either substitution u = sin x or u = cos x will work, but u = easier. d. Either substitution u = sin x or u = cos x will work, but u = cos x would be easier. sin x would bearrow_forwardn/ 2 cos 2.x 6. Consider the integral sin(2x)e°s 2* dx. If u = = cos2x, which expression below is equivalent to the given expression? (A) -S e" du (B) -2f e" du (C) -S e* du (D) S e* du 1 (E) 2f e" duarrow_forward
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