a. Show that the points 1 , 0 , 3 , 10 , and − 2 , 15 are not collinear by finding the slope between 1 , 0 and 3 , 10 , and the slope between 3 , 10 and − 2 , 15 . (See Example 7) b. Find an equation of the form y = a x 2 + b x + c that defines the parabola through the points. c. Use a graphing utility to verify that the graph of the equation in part (b) passes through the given points.
a. Show that the points 1 , 0 , 3 , 10 , and − 2 , 15 are not collinear by finding the slope between 1 , 0 and 3 , 10 , and the slope between 3 , 10 and − 2 , 15 . (See Example 7) b. Find an equation of the form y = a x 2 + b x + c that defines the parabola through the points. c. Use a graphing utility to verify that the graph of the equation in part (b) passes through the given points.
a. Show that the points
1
,
0
,
3
,
10
,
and
−
2
,
15
are not collinear by finding the slope between
1
,
0
and
3
,
10
, and the slope between
3
,
10
and
−
2
,
15
.
(See Example 7)
b. Find an equation of the form
y
=
a
x
2
+
b
x
+
c
that defines the parabola through the points.
c. Use a graphing utility to verify that the graph of the equation in part (b) passes through the given points.
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
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Finding The Focus and Directrix of a Parabola - Conic Sections; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=KYgmOTLbuqE;License: Standard YouTube License, CC-BY