Explanation Given information: Formula used: Area of the triangle is A = 1 2 × b × h , where b : base of the triangle and h : height of the triangle. Area of the rectangle is A = l × w , where l : length of the rectangle and w : width of the rectangle. To determine which property costs less per square foot, first find the area of the given property, and then find the cost per square foot. Lot A has a triangular shape with base b = 135 ft and h = 70 ft . The area of a triangle is A = 1 2 × b × h , Substitute b = 135 ft and h = 70 ft in this formula A = 1 2 × 135 ft×70 ft ⇒ A = 1 2 × 9450 ft 2 ⇒ A = 9450 2 ft 2 ⇒ A = 4725 ft 2 Therefore, the area of Lot A is 4725 ft 2 . Total cost given for Lot A is $ 13 , 500 . Cost per foot can be found by dividing the given total cost of lot A by the area of lot A. So, cost per square foot for Lot A is $ 13 , 500 4725 ft 2 = $ 2

Nature of Mathematics (MindTap Course List)

13th Edition

ISBN: 9781133947257

Author: karl J. smith

Publisher: Cengage Learning

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Chapter 8.2, Problem 41PS

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The property that costs less per square foot from the given figure.

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Chapter 8.2, Problem 40PS

Chapter 8.2, Problem 42PS

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Chapter 8 Solutions

Nature of Mathematics (MindTap Course List)

Ch. 8.1 - IN YOUR OWN WORDS Contrast precision and accuracy.Ch. 8.1 - Prob. 2PS Ch. 8.1 - Prob. 3PS Ch. 8.1 - Prob. 4PS Ch. 8.1 - Prob. 5PS Ch. 8.1 - Prob. 6PS Ch. 8.1 - Prob. 7PS Ch. 8.1 - Prob. 8PS Ch. 8.1 - From memory and without using any measuring...Ch. 8.1 - From memory and without using any measuring...

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Find the...Ch. 8.1 - Prob. 57PS Ch. 8.1 - Prob. 58PS Ch. 8.1 - Prob. 59PS Ch. 8.1 - Prob. 60PS Ch. 8.2 - IN YOUR OWN WORDS What do we mean by area?Ch. 8.2 - Prob. 2PS Ch. 8.2 - Prob. 3PS Ch. 8.2 - Prob. 4PS Ch. 8.2 - Prob. 5PS Ch. 8.2 - Prob. 6PS Ch. 8.2 - Prob. 7PS Ch. 8.2 - Prob. 8PS Ch. 8.2 - Prob. 9PS Ch. 8.2 - Prob. 10PS Ch. 8.2 - Prob. 11PS Ch. 8.2 - Prob. 12PS Ch. 8.2 - Prob. 13PS Ch. 8.2 - Prob. 14PS Ch. 8.2 - Prob. 15PS Ch. 8.2 - Prob. 16PS Ch. 8.2 - Prob. 17PS Ch. 8.2 - Prob. 18PS Ch. 8.2 - Prob. 19PS Ch. 8.2 - Prob. 20PS Ch. 8.2 - Prob. 21PS Ch. 8.2 - Prob. 22PS Ch. 8.2 - Prob. 23PS Ch. 8.2 - Prob. 24PS Ch. 8.2 - Prob. 25PS Ch. 8.2 - Prob. 26PS Ch. 8.2 - Prob. 27PS Ch. 8.2 - Prob. 28PS Ch. 8.2 - Prob. 29PS Ch. 8.2 - Prob. 30PS Ch. 8.2 - Prob. 31PS Ch. 8.2 - Prob. 32PS Ch. 8.2 - Prob. 33PS Ch. 8.2 - Prob. 34PS Ch. 8.2 - Prob. 35PS Ch. 8.2 - Prob. 36PS Ch. 8.2 - Prob. 37PS Ch. 8.2 - Prob. 38PS Ch. 8.2 - Prob. 39PS Ch. 8.2 - Find the area of each shaded region in Problems...Ch. 8.2 - Prob. 41PS Ch. 8.2 - Prob. 42PS Ch. 8.2 - Prob. 43PS Ch. 8.2 - Prob. 44PS Ch. 8.2 - Prob. 45PS Ch. 8.2 - Prob. 46PS Ch. 8.2 - Prob. 47PS Ch. 8.2 - Prob. 48PS Ch. 8.2 - Prob. 49PS Ch. 8.2 - Prob. 50PS Ch. 8.2 - Prob. 51PS Ch. 8.2 - Prob. 52PS Ch. 8.2 - Prob. 53PS Ch. 8.2 - Prob. 54PS Ch. 8.2 - Prob. 55PS Ch. 8.2 - What is the area to the nearest square inch of a...Ch. 8.2 - Find the area to the nearest square inch of the...Ch. 8.2 - Find the area to the nearest square inch of the...Ch. 8.2 - IN YOUR OWN WORDS Extra square centimeter problem...Ch. 8.2 - IN YOUR OWN WORDS Extra square inch problem Figure...Ch. 8.3 - IN YOUR OWN WORDS Contrast length, area, and...Ch. 8.3 - IN YOUR OWN WORDS What do we mean by surface area...Ch. 8.3 - IN YOUR OWN WORDS Contrast volume and capacity.Ch. 8.3 - Compare the size of a cubic inch and a cubic...Ch. 8.3 - Compare the size of a quart and a liter.Ch. 8.3 - Compare a meter and a yard.Ch. 8.3 - In Problems 7-8, find the volume of each solid by...Ch. 8.3 - In Problems 7-8, find the volume of each solid by...Ch. 8.3 - Find the volume of each solid in Problems 9-16.Ch. 8.3 - Find the volume of each solid in Problems 9-16.Ch. 8.3 - Find the volume of each solid in Problems 9-16.Ch. 8.3 - Find the volume of each solid in Problems 9-16.Ch. 8.3 - Find the volume of each solid in Problems 9-16.Ch. 8.3 - Find the volume of each solid in Problems 9-16.Ch. 8.3 - Find the volume of each solid in Problem 9-16.Ch. 8.3 - Find the volume of each solid in Problems 9-16.Ch. 8.3 - Measure each amount given in Problems 17-21....Ch. 8.3 - Measure each amount given in Problems 17-21....Ch. 8.3 - Measure each amount given in Problems 17-21. a....Ch. 8.3 - Measure each amount given in Problems 17-21. a....Ch. 8.3 - Measure each amount given in Problems 17-21. a....Ch. 8.3 - The ability to estimate capacities is an important...Ch. 8.3 - The ability to estimate capacities is an important...Ch. 8.3 - The ability to estimate capacities is an important...Ch. 8.3 - The ability to estimate capacities is an important...Ch. 8.3 - The ability to estimate capacities is an important...Ch. 8.3 - The ability to estimate capacities is an important...Ch. 8.3 - Prob. 28PS Ch. 8.3 - Prob. 29PS Ch. 8.3 - Prob. 30PS Ch. 8.3 - Prob. 31PS Ch. 8.3 - Prob. 32PS Ch. 8.3 - Prob. 33PS Ch. 8.3 - Prob. 34PS Ch. 8.3 - Prob. 35PS Ch. 8.3 - Prob. 36PS Ch. 8.3 - Prob. 37PS Ch. 8.3 - Prob. 38PS Ch. 8.3 - Prob. 39PS Ch. 8.3 - Prob. 40PS Ch. 8.3 - Prob. 41PS Ch. 8.3 - Prob. 42PS Ch. 8.3 - Prob. 43PS Ch. 8.3 - Prob. 44PS Ch. 8.3 - Prob. 45PS Ch. 8.3 - Prob. 46PS Ch. 8.3 - Prob. 47PS Ch. 8.3 - Prob. 48PS Ch. 8.3 - Prob. 49PS Ch. 8.3 - Prob. 50PS Ch. 8.3 - Prob. 51PS Ch. 8.3 - Prob. 52PS Ch. 8.3 - Prob. 53PS Ch. 8.3 - Prob. 54PS Ch. 8.3 - The exterior dimensions of a refrigerator/freezer...Ch. 8.3 - Prob. 56PS Ch. 8.3 - Prob. 57PS Ch. 8.3 - Use the plot shown in Figure 8.20 and give your...Ch. 8.3 - Prob. 59PS Ch. 8.3 - a. 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The property that costs less per square foot from the given figure.

Solution Summary: The author explains how to determine which property costs less per square foot by dividing the cost of lot A by the area of Lot A.

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To find: The property that costs less per square foot from the given figure.

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Chapter 8 Solutions

To find:

The property that costs less per square foot from the given figure.