Explanation Approach: The standard form of the equation of circle is as follows. ( x − h ) 2 + ( y − k ) 2 = r 2 Where, r is the radius of the circle and ( h , k ) is the coordinates of the center of the circle. Calculation: Consider the given circle, x 2 + y 2 − 2 x − 6 y − 6 = 0 Represent the equation of circle in the standard form, x 2 + y 2 − 2 x − 6 y − 6 = 0 ( x 2 − 2 x ) + ( y 2 − 6 y ) = 6 ( x 2 − 2 x + 1 ) + ( y 2 − 6 y + 9 )

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ISBN: 9781305191495

Author: Jerome E. Kaufmann; Karen L. Schwitters

Publisher: Cengage Learning US

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In the study of the conic section of the geometry, An ellipse is a plane curve surrounding two focal points, or foci where the set of all locus of points in the plane has their sum of the distances to the two foci is constant. On the ellipse curve, it is…

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Chapter 8.2, Problem 23PS

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The center and the length of radius of the circle x2+y2−2x−6y−6=0.

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Chapter 8.2, Problem 22PS

Chapter 8.2, Problem 24PS

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Intermediate Algebra

Ch. 8.1 - For Problems 110, answer true or false. The graph...Ch. 8.1 - Prob. 2CQ Ch. 8.1 - Prob. 3CQ Ch. 8.1 - Prob. 4CQ Ch. 8.1 - Prob. 5CQ Ch. 8.1 - Prob. 6CQ Ch. 8.1 - Prob. 7CQ Ch. 8.1 - Prob. 8CQ Ch. 8.1 - Prob. 9CQ Ch. 8.1 - Prob. 10CQ

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The center and the length of radius of the circle x 2 + y 2 − 2 x − 6 y − 6 = 0 .

Solution Summary: The author compares the standard form of the equation of circle, rllx2+y

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To find:

The center and the length of radius of the circle x2+y2−2x−6y−6=0.

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Chapter 8 Solutions

The center and the length of radius of the circle x 2 + y 2 − 2 x − 6 y − 6 = 0 .

Solution Summary: The author compares the standard form of the equation of circle, rllx2+y

Concept explainers

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To find: The center and the length of radius of the circle x2+y2−2x−6y−6=0.

Want to see the full answer?

Chapter 8 Solutions

To find:

The center and the length of radius of the circle x2+y2−2x−6y−6=0.