Explanation Given information: There is only one whole number between 0 and 11 of the equation ( x 2 + 3 x + 7 ) ≡ 2 mod 11 Calculation: Consider the following congruence equation ( x 2 + 3 x + 7 ) ≡ 2 mod 11 Begin with 0; substitute each whole number less than 8 into the congruence equation to get x = 0 0 3 + 3 ( 0 ) + 7 ≠ 2 mod 11 not a solution x = 1 1 3 + 3 ( 1 ) + 7 ≠ 2 mod 11 not a solution x = 2 2 3 + 3 ( 2 ) + 7 ≠ 2 mod 11 not a solution x = 3 3 3 + 3 ( 3 ) + 7 ≠ 2 mod 11 not a solution x = 4 4 3 + 3 ( 4 ) + 7 ≡ 2 mod 11 a solution <

Mathematical Excursions (MindTap Course List)

4th Edition

ISBN: 9781305965584

Author: Richard N. Aufmann, Joanne Lockwood, Richard D. Nation, Daniel K. Clegg

Publisher: Cengage Learning

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Chapter 8.1, Problem 97ES

To determine

To calculate:

To find the solution of the equation (x2+3x+7)≡2mod11

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Chapter 8.1, Problem 96ES

Chapter 8.1, Problem 98ES

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Mathematical Excursions (MindTap Course List)

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