Let T : V → W be a linear transformation, and suppose that { v 1 , v 2 , … , v n } is a basis of ker ( T ) . Prove that every solution to the operator equation, T ( v ) = w (8.1.15) Is of the form v = c 1 v 1 + c 2 v 2 + ⋯ + c n v n + v p Where v p is the particular solution to equation (8.1.15).
Let T : V → W be a linear transformation, and suppose that { v 1 , v 2 , … , v n } is a basis of ker ( T ) . Prove that every solution to the operator equation, T ( v ) = w (8.1.15) Is of the form v = c 1 v 1 + c 2 v 2 + ⋯ + c n v n + v p Where v p is the particular solution to equation (8.1.15).
Solution Summary: The author proves that the solution to the given operator equation is of the form v=c_1. Let T:Vto W be a linear transformation.
Let
T
:
V
→
W
be a linear transformation, and suppose that
{
v
1
,
v
2
,
…
,
v
n
}
is a basis of
ker
(
T
)
. Prove that every solution to the operator equation,
T
(
v
)
=
w
(8.1.15)
Is of the form
v
=
c
1
v
1
+
c
2
v
2
+
⋯
+
c
n
v
n
+
v
p
Where
v
p
is the particular solution to equation (8.1.15).
I want to learn this topic l dont know anything about it
Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
Chapter 8 Solutions
Differential Equations and Linear Algebra (4th Edition)
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