
Concept explainers
(a)
To sketch: the curve of the given parametric equations
(a)

Answer to Problem 8RCC
The procedure to sketch the curve of the parametric equations is explained.
Explanation of Solution
Given:
Calculation:
The procedure to sketch the curve of the parametric equations
If f and g are functions defined on an interval I , then the set of points
For different value of t, get a point on the curve and then write these values in a table.
For example, if
So the corresponding point is
Then, plot the points
Conclusion:
Therefore, the procedure to sketch the curve of the parametric equations is explained.
(b)
To explain: eliminate the parameter.
(b)

Answer to Problem 8RCC
The parameter is eliminated.
Explanation of Solution
Calculation:
The method to eliminate the parameter:
The curve given by parametric equations can be represented by a single rectangular equation in x and y .
The process of finding this equation is called eliminating the parameter.
Solve for parameter in one equation, and then substitute its value into the other equation.
Thus, the parameter is eliminated.
Conclusion:
Therefore, the parameter is eliminated.
Chapter 8 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
- Solve please thanks!arrow_forwardSolve please and thank youarrow_forwardAccording to Newton's law of universal gravitation, the force F between two bodies of constant mass GmM m and M is given by the formula F = , where G is the gravitational constant and d is the d² distance between the bodies. a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to distance d. F' (d) 2GmM b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation, rounding to 2 decimal places. -6.67x10 N/m syntax incomplete.arrow_forward
- Solve please and thank youarrow_forwardmv2 The centripetal force of an object of mass m is given by F (r) = rotation and r is the distance from the center of rotation. ' where v is the speed of r a. Find the rate of change of centripetal force with respect to the distance from the center of rotation. F(r) b. Find the rate of change of centripetal force of an object with mass 500 kilograms, velocity of 13.86 m/s, and a distance from the center of rotation of 300 meters. Round to 2 decimal places. N/m (or kg/s²) F' (300)arrow_forwardSolve work shown please and thanks!arrow_forward
- Given the following graph of the function y = f(x) and n = = 6, answer the following questions about the area under the curve from x graph to enlarge it.) 1 (Round your answer to within two decimal places if necessary, but do not round until your final computation.) a. Use the Trapezoidal Rule to estimate the area. Estimate: T6 G b. Use Simpson's Rule to estimate the area. Estimate: S6 - ID = 0 to x = 6. (Click on aarrow_forward"Solve the following differential equation using the Operator Method and the Determinant Method:" Solve by dr no ai """'+3y"" + 3y+y=arrow_forward(4,4) M -4 2 2 -4 (-4,-4) 4 8 10 12 (8,-4) (12,-4) Graph of f The figure shows the graph of a piecewise-linear function f. For −4≤x≤12, the function g is x defined by g(x) = √ƒ (t)dt . . Find the value of g(6). Find the value of g'(6). |arrow_forward
- PREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE ANOTHER Find the derivative of the function. f'(x) = X x + √3x f(x) = 3x-5 (3√√3x+11√√x+5√3 2√√x (3x-5)² Need Help? Read It SUBMIT ANSWERarrow_forwardPREVIOUS ANSWERS ASK YOUR TEACHER PRACTICE A Find the derivative of the function and evaluate f'(x) at the given val f(x) = (√√√x + 3x) (x3/2 - x); x = 1 f'(x) = 9x 412 (12x (13) 2 - 4x-3√√√x f'(1) = 2 Need Help? Read It Watch It SUBMIT ANSWERarrow_forwardConsider the following functions. g(x) = x + √3x h(x) = 3x-5 x + √3x f(x) = = 3x-5 Find the derivative of each function. g'(x) h'(x) = = f'(x) = 3 = +1 2√3x 3 (3√3x + 10√√x +5√√√3 2√√x (3x-5)² Need Help? Read It SUBMIT ANSWERarrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





