Chapter 8, Problem 8.EE

(a)

Interpretation Introduction

Interpretation:

The amount of $\text{KI}$ required to reach the equivalence point is $\text{32}\text{.0}\text{mL}$ this has to be verified.

(b)

Interpretation Introduction

Interpretation:

The ionic strength when $\text{60}\text{.0}\text{mL}\text{of}\text{KI}$ have been added to the solution has to be calculated.

Concept introduction:

Ionic strength $\left(\mu \right)$:

The ionic strength $\left(\text{μ}\right)$ of the solution is given by

$\begin{array}{l}\text{μ}\text{=}\frac{\text{1}}{\text{2}}\left({\text{c}}_{\text{1}}{\text{z}}_{\text{1}}^{\text{2}}\text{+}{\text{c}}_{\text{2}}{\text{z}}_{\text{2}}^{\text{2}}\text{+}\mathrm{.......}\right)\text{=}\frac{\text{1}}{\text{2}}{\displaystyle \sum _{\text{i}}{\text{c}}_{\text{i}}{\text{z}}_{\text{i}}{}^{\text{2}}}\\ \text{where,}\\ {\text{c}}_{\text{i}}\text{-}\text{concentration}\text{of}\text{the}{\text{i}}^{\text{th}}\text{species}\text{and}{\text{z}}_{\text{i}}\text{-}\text{is}\text{its}\text{charge}\text{.}\end{array}$

(c)

Interpretation Introduction

Interpretation:

The value of ${\text{pHg}}_{\text{2}}^{\text{2+}}\left(\text{=}\text{-}\text{log}{\text{A}}_{{\text{Hg}}_{\text{2}}^{\text{2+}}}\right)$ for part (b) has to be calculated.

Concept introduction:

Activity of species:

The activity value of any species is obtained by multiplying its concentration with its activity coefficient.

$\begin{array}{l}\text{For}\text{a}\text{species}\text{C, the}\text{activity}\text{is}\text{given}\text{by}\\ {\text{A}}_{\text{C}}\text{=}\left[\text{C}\right]{\text{γ}}_{\text{C}}\\ \text{where,}\\ \text{A}\text{-}\text{Activity}\\ \left[\right]\text{-}\text{Concentration}\\ \text{γ}\text{-}\text{Activity}\text{coefficient}\end{array}$