Chapter 8, Problem 89QP

Predict the parent structures of the following molecules.

$\begin{array}{l}\text{(a)}{\text{BeCl}}_{\text{2}}\\ \text{(b)}{\text{PH}}_{\text{3}}\\ \text{(c)}{\text{SCl}}_{\text{2}}\\ \text{(d)}{\text{SO}}_{\text{2}}\\ \text{(e)}{\text{H}}_{\text{2}}\text{Te}\\ \text{(f)}{\text{SiH}}_{\text{4}}\\ \text{(g)}{\text{BBr}}_{\text{3}}\\ \text{(h)}{\text{H}}_{\text{2}}\text{O}\end{array}$

Interpretation Introduction

Interpretation:

The parent structure of ${\text{BeCl}}_{\text{2}}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results in the parent structure or geometry of the molecule.

There are two electron domains present in ${\text{BeCl}}_{\text{2}}$ as there are two bonded chlorine atoms. Thus, the Lewis structure of ${\text{BeCl}}_{\text{2}}$ is drawn below.

Thus, the parent structure of ${\text{BeCl}}_{\text{2}}$ is linear as the electron domain is two.

Interpretation Introduction

Interpretation:

The parent structure of ${\text{PH}}_{\text{3}}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results to the parent structure or geometry of the molecule.

There are four electron domains present in the ${\text{PH}}_{\text{3}}$ as there are three bonded hydrogen atoms and one unshared electron pair. Thus, the lewis structure of ${\text{PH}}_{\text{3}}$ is drawn below.

Thus, the parent structure of ${\text{PH}}_{\text{3}}$ is tetrahedral as an electron domain is four.

Interpretation Introduction

Interpretation:

The parent structure of ${\text{SCl}}_{\text{2}}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results in the parent structure or geometry of the molecule.

There are four electron domains present in ${\text{SCl}}_{\text{2}}$ as there are two bonded chlorine atoms and two unshared electron pairs. Thus, the lewis structure of ${\text{SCl}}_{\text{2}}$ is drawn below.

Thus, the parent structure of ${\text{SCl}}_{\text{2}}$ is tetrahedral as the electron domain is four.

Interpretation Introduction

Interpretation:

The parent structure of ${\text{SO}}_{\text{2}}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results in the parent structure or geometry of the molecule.

There are three electron domains present in the ${\text{SO}}_{\text{2}}$ as there are two bonded oxygen atoms and one unshared electron pairs. Thus, the lewis structure of ${\text{SO}}_{\text{2}}$ is drawn below.

Thus, the parent structure of ${\text{SO}}_{\text{2}}$ is a trigonal planar as the electron domain is three.

Interpretation Introduction

Interpretation:

The parent structure of ${\text{H}}_{\text{2}}\text{Te}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results in the parent structure or geometry of the molecule.

There are four electron domains present in ${\text{H}}_{\text{2}}\text{Te}$ as there are two bonded hydrogen atoms and two unshared electron pairs. Thus, the lewis structure of ${\text{H}}_{\text{2}}\text{Te}$ is drawn below.

Thus, the parent structure of ${\text{H}}_{\text{2}}\text{Te}$ is tetrahedral as the electron domain is four.

Interpretation Introduction

Interpretation:

The parent structure of ${\text{SiH}}_{\text{4}}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results in the parent structure or geometry of the molecule.

There are four electron domains present in ${\text{SiH}}_{\text{4}}$ as there are only four bonded hydrogen atoms. Thus, the lewis structure of ${\text{SiH}}_{\text{4}}$ is drawn below.

Thus, the parent structure of ${\text{SiH}}_{\text{4}}$ is tetrahedral as the electron domain is four.

Interpretation Introduction

Interpretation:

The parent structure of ${\text{BBr}}_{\text{3}}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results in the parent structure or geometry of the molecule.

There are three electron domains present in the ${\text{BBr}}_{\text{3}}$ as there are only three bonded bromine atoms. Thus, the lewis structure of ${\text{BBr}}_{\text{3}}$ is drawn below.

Thus, the parent structure of ${\text{BBr}}_{\text{3}}$ is a trigonal planar as the electron domain is three.

Interpretation Introduction

Interpretation:

The parent structure of ${\text{H}}_{\text{2}}\text{O}$ is to be stated.

Explanation of Solution

The sum of atoms attached to the central metal atom and the unshared electron pairs is termed as electron domains. The electron domains are calculated by drawing the Lewis structure which results in the parent structure or geometry of the molecule.

There are four electron domains present in the ${\text{H}}_{\text{2}}\text{O}$ as there are only two bonded hydrogen atoms and two unshared electron pairs. Thus, the lewis structure of ${\text{H}}_{\text{2}}\text{O}$ is drawn below.

Thus, the parent structure of ${\text{H}}_{\text{2}}\text{O}$ is tetrahedral as the electron domain is four.