Practice of Statistics in the Life Sciences
Practice of Statistics in the Life Sciences
4th Edition
ISBN: 9781319013370
Author: Brigitte Baldi, David S. Moore
Publisher: W. H. Freeman
Question
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Chapter 8, Problem 8.9CRE

a.

To determine

To construct: A plot using the distribution of neuronal response to a pure tone and find the numerical summary. Also check whether there outliers exist or not, if yes then again find the numerical summary by omitting it and explain their influence.

a.

Expert Solution
Check Mark

Explanation of Solution

Given:

The dataset:

    NeuronToneCallNeuronToneCall
    147450020100118
    2256138217462
    32414852272112
    42263382320193
    51851942421129
    61741592526135
    71763412671134
    816885276865
    91613032859182
    10150208295997
    1119663057318
    1220543156201
    13351033247279
    1414542334662
    15141241344184
    161291943526203
    171131233628192
    18112182373170
    19102141

Formula used:

The formula to compute the correlation is:

  r=n(xy)(x)(y)n(x2)(x)2n(y2)(y)2

Graph:

The scatter plot could be constructed as:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  1

Interpretation:

From the above scatter plot, it is clear that the value 474 is an outlier because it is far distant from the other values.

Calculation:

The numerical summary is:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  2

After removal of outlier, the value of the correlation is:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  3

From above output, it is clear that omission of outlier has led the reduction in the value of correlation between the two variables

b.

To determine

To construct: A plot using the distribution of neuronal response to a monkey call and find the numerical summary. Also check whether there outliers exist or not, if yes then again find the numerical summary by omitting it and explain their influence.

b.

Expert Solution
Check Mark

Explanation of Solution

Graph:

The scatter plot could be constructed as:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  4

Interpretation:

From the above scatter plot, it is clear that the values 484 and 500 are outlier because they are far distant from the other values.

Calculation:

The numerical summary is:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  5

After removal of outlier, the value of the correlation is:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  6

From above output, it is clear that omission of outlier has led increase in the value of correlation between the two variables

c.

To determine

To construct the pie chart or bar chart to show the proportion of given categories.

c.

Expert Solution
Check Mark

Explanation of Solution

Given:

The categories:

Very low birth weight: Less than 1500 grams

Low birth weight: Less than 2500 grams

Normal birth weight: More than 2500 grams

Calculation:

Count of each category:

    Category Frequency Proportion
    Very low birth Weight578410.0144768
    Low birth weight2677220.0670072
    Normal birth weight36698590.918516

Graph:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  7

d.

To determine

To check: whether there any relationship exists between the variables call and tone response by constructing scatter plot and explain it. Also, compute the numerical summary, if possible.

d.

Expert Solution
Check Mark

Explanation of Solution

Graph:

The scatter plot could be constructed as:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  8

Interpretation:

The above scatter plot shows that there is a positive correlation between the two variables despite the presence of outlier in the data set.

Calculation:

The correlation between the two variables can be calculated as:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.9CRE , additional homework tip  9

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