Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 8, Problem 8.6P
To determine
Draw the flow net for the weir and calculate the seepage under the weir.
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Draw a flow net for the weir shown in Figure 8.20. Calculate the rate of seepage
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Impermeable layer
Figure 8.20
Draw a flow net for the weir shown in Figure below. Calculate the rate of seepage under the
weir.
37 m
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For the concrete Dam shown in figure, determine the total average seepage for the given permeable strata by drawing Flow Net. The detail dimensions are given on the figure. The head of water on upstream side is 6ft and on downstream side is 1ft. Assume of Nf= 3, Nd= 6 and rectangular flow elements
Chapter 8 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- Show complete solution(need ASAP): The coefficient of permeability below a dam is 4 m/day. The water on the upstream side is 20 m. higher than on the downstream side. To estimate the seepage below the dam, a flow net was graphically drawn. The base of the dam is founded 1 meter below the ground. Between the heel and the toe of the dam, a distance of 30 m, there are 8 potential drops. a. Evaluate the seepage flow per meter length of the dam in cu.m per day. b. Compute the uplift force per unit length along the axis of the dam in kN/m. c. Determine the position of the uplift force from the toe of the dam in m.arrow_forwardHow can I calculate the water level in a grit chamber at average flow and at peak hourly flow. The effluent from the tank flows over a fiberglass, sharp-crested weir that is set at elevation 136.00 ft above sea level (ASL). The average daily flow rate is 2.6 MGD. Assume that all flow must pass through one grit chamber. The dimensions of the grit chamber are 9 ft wide, 30 ft long, and 10.5 ft deep (water depth). The weir extends across the full width of the chamber. Peak hourly flow rate = _____MGDarrow_forwardHow can I calculate the water level in a grit chamber at average flow and at peak hourly flow. The effluent from the tank flows over a fiberglass, sharp-crested weir that is set at elevation 136.00 ft above sea level (ASL). The average daily flow rate is 2.6 MGD. Assume that all flow must pass through one grit chamber. The dimensions of the grit chamber are 9 ft wide, 30 ft long, and 10.5 ft deep (water depth). The weir extends across the full width of the chamber and find the hydraulic retention time of the grit chamber. HRT at average flow = ______ minutesand HRT at peak hourly flow = ______ minutesarrow_forward
- How can I calculate the water level in a grit chamber at average flow and at peak hourly flow. The effluent from the tank flows over a fiberglass, sharp-crested weir that is set at elevation 136.00 ft above sea level (ASL). The average daily flow rate is 2.6 MGD. Assume that all flow must pass through one grit chamber. The dimensions of the grit chamber are 9 ft wide, 30 ft long, and 10.5 ft deep (water depth). The weir extends across the full width of the chamber.Elevation of water in grit chamber at average daily flow = ______ ASLarrow_forwardDraw a flow net for the weir shown in Figure B, then calculate the rate of seepage under the weir. In addition, evaluate the exit gradient in the first flow channel of the last field against the critical gradient. Assume e = 0.60, and G, = 2.60, 37 m 10 m 1.5 m 3 m 9 m Sheet pile 24 m k = 1 x 10-3cm/sec Impermeable Layerarrow_forwardA1arrow_forward
- 5- An earth dam is shown below. Determine the seepage rate, q, in ft/day/ft length. Given: a1=35°, az=40°, L1=5 ft, H=7 ft, Hj=10 ft, and 3X104 ft/sec. Water level k H a2 Impervious basearrow_forwardA primary clarifier for a municipal wastewater treatment plant is to be designed for an average flow of 7570 m3/d. the regulatory agency criteria for primary clarifiers are as follows: peak overflow rate = 89.6 m3/m2.d, average overflow rate = 36.7 m3/m2d, minimum side water depth = 3 m, and peak weir loading rate = 389 m3/m.d. The ratio of peak flow to average flow = 2.75. Determine: Diameter of the sedimentation basin The length of the peripheral weir. Assume that the weir launder has a width of 50 cm (from the tank side), and the weirs are installed on one side of the launder.arrow_forwardCompute the hydraulic radius and hydraulic depthj for a 36 inch diameter culvert with a depth of flow of 20 inchesarrow_forward
- A concrete pipe culvert 3 ft in diameter and 10 m long has a difference in water level at the outlet 1.52 m. What is the discharge? Assume coefficient of discharge C = 0.74 1.52 L=10m 28.57 m^3/s 2.66 m^3/s 50.78 m^3/s 4.72 m^3/sarrow_forwardA rectangular open channel is 4m wide and has a discharge of 10 cu.m./s when the depth of flow is 2m. If the same material has been used for a trapezoidal open channel having the same wetted perimeter, what would be the most efficient discharge without changing the slope? a) Q = Blank 1 cubic meters/sec. Blank 1 Add your answerarrow_forwardAt one section of a 300 cm wide rectangular channel, the depth of flow is 180 cm. With a bed of 0.0020, the channel is discharging water at a rate of 3.40 m³/s. Calculate the distance to an upstream section where the depth of flow is 1.50 m. Draw and label your solution. Show the Energy grade line. Assume n = 0.015 Distance = m (round off to nearest whole number)arrow_forward
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