Chapter 8, Problem 8.59EP

(a)

Interpretation Introduction

Interpretation:

The number of liters of $\text{0}\text{.100 M}$ solution prepared from $\text{60}\text{.0 g}$ of ${\text{NaNO}}_{\text{3}}$ has to be calculated.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution. The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$

(b)

Interpretation Introduction

Interpretation:

The number of liters of $\text{0}\text{.100 M}$ solution prepared from $\text{60}\text{.0 g}$ of ${\text{HNO}}_{\text{3}}$ has to be calculated.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution. The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$

(c)

Interpretation Introduction

Interpretation:

The number of liters of $\text{0}\text{.100 M}$ solution prepared from $\text{60}\text{.0 g}$ of $\text{KOH}$ has to be calculated.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution. The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$

(d)

Interpretation Introduction

Interpretation:

The number of liters of $\text{0}\text{.100 M}$ solution prepared from $\text{60}\text{.0 g}$ of $\text{LiCl}$ has to be calculated.

Concept Introduction:

Molarity: It is defined as number of moles of solute present in one liter of solution. The mathematical formula for molarity is given as,

$\text{Molarity}\text{=}\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}\text{(mol)}}{\text{Volume}\text{of}\text{solution(L)}}$