(a)
Interpretation:
The reason for the increase in the successive
Concept introduction:
The ionization energy is the amount of energy required to remove the most loosely bound valence electrons from an isolated neutral gaseous atom. It is represented by IE.
When the first electron is removed from the parent atom it is called first ionization energy
Its value varies with the ease of removal of the outermost valence electron. If the outermost electron is removed very easily then the value of ionization energy is very small. If the electron is removed with quite difficulty then the value of ionization energy will be very high. It increases along the period and decreases from top to bottom in a group.
(b)
Interpretation:
The nature of the element’s electronic configuration when the difference between the successive
Concept introduction:
The ionization energy is the amount of energy required to remove the most loosely bound valence electrons from an isolated neutral gaseous atom. It is represented by IE.
When the first electron is removed from the parent atom it is called first ionization energy
Its value varies with the ease of removal of the outermost valence electron. If the outermost electron is removed very easily then the value of ionization energy is very small. If the electron is removed with quite difficulty then the value of ionization energy will be very high. It increases along the period and decreases from top to bottom in a group.
(c)
Interpretation:
The element and its complete electronic configuration if it is assumed to belong to the following is to be determined.
Concept introduction:
The electronic configuration tells about the distribution of electrons in various atomic orbitals. It is used to predict the physical and chemical properties of the elements.
A period in the periodic table is a row of the chemical elements. There are seven periods in the periodic table. All the elements of the same period have same number of atomic orbitals.
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Chapter 8 Solutions
CHEMISTRY(LOOSELEAF) W/CONNECT+EBOOK
- 1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forward
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
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