The element with the configuration [ He ] 2 s 2 2 p 1 is to be identified. Also the symbols of the other elements in its group are to be written. Concept introduction: The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

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Answer 1

Question

Chapter 8, Problem 8.39P

(a)

Interpretation Introduction

Interpretation:

The element with the configuration [He] 2s22p1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(b)

Interpretation Introduction

Interpretation:

The element with the configuration [Ne] 3s23p4 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(c)

Interpretation Introduction

Interpretation:

The element with the configuration [Xe] 6s25d1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

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Topic: Photochemistry and Photophysics of Supramolecules

Two cations that exchange an electron in an interface, the exchange density is worth 1.39 mA/cm2 and the current density is worth 15 mA/cm2 at 25°C. If the overvoltage is 0.14 V, calculate the reaction rate and symmetry factor. Data: R = 8,314 J mol-1 k-1: F = 96500 C

With the help of the Tafel line, it is estimated that the interchange density of the VO2+/VO2+ system on the carbon paper has a value of 3 mA cm-2. Calculate a) the current density if the voltage has a value of 1.6 mV and the temperature is 25°C. b) the beta value of the anódico process if the Tafel pendulum is 0.6 V at 25°C. Data: R = 8.314 JK-1mol-1, y F = 96485 C mol-1.

Answer 2

Question

Chapter 8, Problem 8.39P

(a)

Interpretation Introduction

Interpretation:

The element with the configuration [He] 2s22p1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(b)

Interpretation Introduction

Interpretation:

The element with the configuration [Ne] 3s23p4 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(c)

Interpretation Introduction

Interpretation:

The element with the configuration [Xe] 6s25d1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

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Answer 3

Question

Chapter 8, Problem 8.39P

(a)

Interpretation Introduction

Interpretation:

The element with the configuration [He] 2s22p1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(b)

Interpretation Introduction

Interpretation:

The element with the configuration [Ne] 3s23p4 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(c)

Interpretation Introduction

Interpretation:

The element with the configuration [Xe] 6s25d1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

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Answer 4

Question

Chapter 8, Problem 8.39P

(a)

Interpretation Introduction

Interpretation:

The element with the configuration [He] 2s22p1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(b)

Interpretation Introduction

Interpretation:

The element with the configuration [Ne] 3s23p4 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(c)

Interpretation Introduction

Interpretation:

The element with the configuration [Xe] 6s25d1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

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Answer 5

Chapter 8, Problem 8.39P

(a)

Interpretation Introduction

Interpretation:

The element with the configuration [He] 2s22p1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(b)

Interpretation Introduction

Interpretation:

The element with the configuration [Ne] 3s23p4 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

(c)

Interpretation Introduction

Interpretation:

The element with the configuration [Xe] 6s25d1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

Answer 6

Chapter 8, Problem 8.39P

(a)

Interpretation Introduction

Interpretation:

The element with the configuration [He] 2s22p1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

Answer 7

Chapter 8, Problem 8.39P

(a)

Interpretation Introduction

Interpretation:

The element with the configuration [He] 2s22p1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The element with the configuration [Ne] 3s23p4 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The element with the configuration [Ne] 3s23p4 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The element with the configuration [Xe] 6s25d1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The element with the configuration [Xe] 6s25d1 is to be identified. Also the symbols of the other elements in its group are to be written.

Concept introduction:

The atomic number is equal to the number of protons present in the nucleus of the atom. It is a fundamental property of the atom. It is used to identify an atom and its chemical properties. It is also equal to the number of electrons in an uncharged species.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 8.2 - Use the periodic table to identify the element...Ch. 8.2 - Prob. 8.1BFP Ch. 8.2 - Prob. 8.2AFP Ch. 8.2 - Prob. 8.2BFP Ch. 8.3 - Prob. 8.3AFP Ch. 8.3 - Prob. 8.3BFP Ch. 8.3 - Prob. 8.4AFP Ch. 8.3 - Prob. 8.4BFP Ch. 8.3 - Prob. 8.5AFP Ch. 8.3 - Prob. 8.5BFP

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