Student Solutions Manual for Ball's Physical Chemistry, 2nd
2nd Edition
ISBN: 9798214169019
Author: David W. Ball
Publisher: Cengage Learning US
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Chapter 8, Problem 8.37E
Interpretation Introduction
Interpretation: The
Concept introduction: An electrochemical cell is a combination of two half cells in which a wire and a salt bridge join two electrodes. Electrons flow from anode to cathode. Cell potential is defined as the measure of energy per unit charge available from the
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Write the complete common (not IUPAC) name of each molecule below.
Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is.
molecule
Ο
C=O
common name
(not the IUPAC
name)
H
☐
H3N
CH₂OH
0-
C=O
H
NH3
CH₂SH
H3N
☐
☐
X
G
(Part A) Provide structures of the FGI products and missing reagents (dashed box)
1 eq Na* H*
H
-H
B1
B4
R1
H2 (gas)
Lindlar's
catalyst
A1
Br2
MeOH
H2 (gas)
Lindlar's
catalyst
MeO.
OMe
C6H1402
B2
B3
A1
Product carbons' origins
Draw a box around product
C's that came from A1.
Draw a dashed box around
product C's that came from B1.
Classify each of the amino acids below.
Note for advanced students: none of these amino acids are found in normal proteins.
X
CH2
H3N-CH-COOH3N-CH-COO-
H3N-CH-COO
CH2
CH3-C-CH3
CH2
NH3
N
NH
(Choose one) ▼
(Choose one)
S
CH2
OH
(Choose one) ▼
+
H3N-CH-COO¯
CH2
H3N CH COO H3N-CH-COO
CH2
오오
CH
CH3
CH2
+
O
C
CH3
O=
O_
(Choose one)
(Choose one) ▼
(Choose one)
G
Chapter 8 Solutions
Student Solutions Manual for Ball's Physical Chemistry, 2nd
Ch. 8 - 8.1. What is the charge on a small sphere that is...Ch. 8 - 8.2. The force of attraction due to gravity...Ch. 8 - 8.3. Two small metallic bodies are given opposite...Ch. 8 - Prob. 8.4ECh. 8 - What is the force of attraction between a...Ch. 8 - Prob. 8.6ECh. 8 - 8.7. How much work is required to move a single...Ch. 8 - 8.8. Explain why an electromotive force is not, in...Ch. 8 - Prob. 8.9ECh. 8 - For each of the following reactions, determine the...
Ch. 8 - Prob. 8.11ECh. 8 - Prob. 8.12ECh. 8 - 8.13. Is the disproportionation reaction...Ch. 8 - Prob. 8.14ECh. 8 - Prob. 8.15ECh. 8 - Prob. 8.16ECh. 8 - Prob. 8.17ECh. 8 - 8.18. Determine and for each of the following...Ch. 8 - Prob. 8.19ECh. 8 - Prob. 8.20ECh. 8 - Prob. 8.21ECh. 8 - Prob. 8.22ECh. 8 - Prob. 8.23ECh. 8 - Prob. 8.24ECh. 8 - Prob. 8.25ECh. 8 - Prob. 8.26ECh. 8 - Prob. 8.27ECh. 8 - What is the Zn2+:Cu2+ ratio on a Daniell cell that...Ch. 8 - Prob. 8.29ECh. 8 - Determine the voltage of this reaction with the...Ch. 8 - The thermite reaction can act as the basis of an...Ch. 8 - A concentration cell has different concentrations...Ch. 8 - Prob. 8.34ECh. 8 - Prob. 8.35ECh. 8 - a What is the equilibrium constant for the...Ch. 8 - Prob. 8.37ECh. 8 - Prob. 8.38ECh. 8 - Prob. 8.39ECh. 8 - Prob. 8.40ECh. 8 - Prob. 8.41ECh. 8 - Consider the following formation reaction for HI:...Ch. 8 - Prob. 8.43ECh. 8 - 8.44. Determine an expression for , the change in...Ch. 8 - Prob. 8.45ECh. 8 - Prob. 8.46ECh. 8 - Determine the equilibrium constant for the...Ch. 8 - Prob. 8.48ECh. 8 - Prob. 8.49ECh. 8 - What is the solubility product constant of Hg2Cl2,...Ch. 8 - Prob. 8.51ECh. 8 - Prob. 8.52ECh. 8 - Prob. 8.53ECh. 8 - Prob. 8.54ECh. 8 - Prob. 8.55ECh. 8 - Prob. 8.56ECh. 8 - Prob. 8.57ECh. 8 - Show that a can be written as n+mnn+n+nn, where m...Ch. 8 - Prob. 8.59ECh. 8 - Prob. 8.60ECh. 8 - What molality of NaCl is necessary to have the...Ch. 8 - Prob. 8.62ECh. 8 - Prob. 8.63ECh. 8 - Calculate the molar enthalpy of formation of I(aq)...Ch. 8 - Prob. 8.65ECh. 8 - Hydrofluoric acid, HF(aq), is a weak acid that is...Ch. 8 - Prob. 8.68ECh. 8 - Prob. 8.69ECh. 8 - Prob. 8.70ECh. 8 - Prob. 8.71ECh. 8 - Prob. 8.72ECh. 8 - The mean activity coefficient for an aqueous...Ch. 8 - Human blood plasma is approximately 0.9NaCl. What...Ch. 8 - Under what conditions does the extended...Ch. 8 - Prob. 8.76ECh. 8 - Approximate the expected voltage for the following...Ch. 8 - Prob. 8.78ECh. 8 - Prob. 8.79ECh. 8 - Prob. 8.80ECh. 8 - a The salt NaNO3 can be thought of as...Ch. 8 - Prob. 8.82ECh. 8 - What is the estimated velocity for Cu2+ ions...Ch. 8 - Prob. 8.84ECh. 8 - Prob. 8.85ECh. 8 - Prob. 8.86ECh. 8 - Calculate a the solubility product constant for...
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- Another standard reference electrode is the standard calomel electrode: Hg2Cl2(s) (calomel) + 2e2 Hg() +2 Cl(aq) This electrode is usually constructed with saturated KCI to keep the Cl- concentration constant (similar to what we discussed with the Ag-AgCl electrode). Under these conditions the potential of this half-cell is 0.241 V. A measurement was taken by dipping a Cu wire and a saturated calomel electrode into a CuSO4 solution: saturated calomel electrode potentiometer copper wire CuSO4 a) Write the half reaction for the Cu electrode. b) Write the Nernst equation for the Cu electrode, which will include [Cu2+] c) If the voltage on the potentiometer reads 0.068 V, solve for [Cu²+].arrow_forward2. (Part B). Identify a sequence of FGI that prepares the Synthesis Target 2,4-dimethoxy- pentane. All carbons in the Synthesis Target must start as carbons in either ethyne, propyne or methanol. Hint: use your analysis of Product carbons' origins (Part A) to identify possible structure(s) of a precursor that can be converted to the Synthesis Target using one FGI. All carbons in the Synthesis Target must start as carbons in one of the three compounds below. H = -H H = -Me ethyne propyne Synthesis Target 2,4-dimethoxypentane MeOH methanol OMe OMe MeO. OMe C₂H₁₂O₂ Product carbons' origins Draw a box around product C's that came from A1. Draw a dashed box around product C's that came from B1.arrow_forwardDraw the skeletal ("line") structure of the smallest organic molecule that produces potassium 3-hydroxypropanoate when reacted with KOH. Click and drag to start drawing a structure. Sarrow_forward
- draw skeletal structures for the minor products of the reaction.arrow_forward1. Provide missing starting materials, reagents, products. If a product cannot be made, write NP (not possible) in the starting material box. C7H12O Ph HO H 1) 03-78 C 2) Me₂S + Ph .H OH + 2nd stereoisomer OH Ph D + enantiomer cat OsO 4 NMO H2O acetonearrow_forwardPlease note that it is correct and explains it rightly:Indicate the correct option. The proportion of O, C and H in the graphite oxide is:a) Constant, for the quantities of functional groups of acids, phenols, epoxy, etc. its constants.b) Depending on the preparation method, as much oxidant as the graphite is destroyed and it has less oxygen.c) Depends on the structure of the graphic being processed, whether it can be more tridimensional or with larger crystals, or with smaller crystals and with more edges.arrow_forward
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