(a)
Interpretation:
The condensed electron configuration and the group number with the help of the partial(valence level) orbital diagram of following is to be determined.
Concept introduction:
The partial orbital diagram is the one that shows the distribution of valence electrons only.
The condensed electronic configuration is a way to write the electronic configuration where the inner shell configurations are compressed to the nearest noble gas configuration and only the valence shell configuration is written in the expanded form.
The group number tells about the group to which the concerned element belongs. The number of valence electrons is equal to the group number.
(b)
Interpretation:
The condensed electron configuration and the group number with the help of the partial(valence level) orbital diagram of following is to be determined.
Concept introduction:
The partial orbital diagram is the one that shows the distribution of valence electrons only.
The condensed electronic configuration is a way to write the electronic configuration where the inner shell configurations are compressed to the nearest noble gas configuration and only the valence shell configuration is written in the expanded form.
The group number tells about the group to which the concerned element belongs.
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Chapter 8 Solutions
CHEMISTRY: MOLECULAR NATURE OF MATTER
- Give the major product of the following reaction. excess 1. OH, H₂O 1.OH H CH3CH2CH21 H 2. A.-H₂O Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default.arrow_forward2. Use Hess's law to calculate the AH (in kJ) for: rxn CIF(g) + F2(g) → CIF 3 (1) using the following information: 2CIF(g) + O2(g) → Cl₂O(g) + OF 2(g) AH = 167.5 kJ ΔΗ 2F2 (g) + O2(g) → 2 OF 2(g) 2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g) о = = -43.5 kJ AH = 394.1kJarrow_forwardci Draw the major product(s) of the following reactions: (3 pts) CH3 HNO3/H2SO4 HNO3/ H2SO4 OCH3 (1 pts)arrow_forward
- What is the molecular formula of the bond-line structure shown below OH HO ○ C14H12O2 ○ C16H14O2 ○ C16H12O2 O C14H14O2arrow_forwardCheck all molecules that are acids on the list below. H2CO3 HC2H3O2 C6H5NH2 HNO3 NH3arrow_forwardFrom the given compound, choose the proton that best fits each given description. a CH2 CH 2 Cl b с CH2 F Most shielded: (Choose one) Least shielded: (Choose one) Highest chemical shift: (Choose one) Lowest chemical shift: (Choose one) ×arrow_forward
- Consider this molecule: How many H atoms are in this molecule? How many different signals could be found in its 1H NMR spectrum? Note: A multiplet is considered one signal.arrow_forwardFor each of the given mass spectrum data, identify whether the compound contains chlorine, bromine, or neither. Compound m/z of M* peak m/z of M + 2 peak ratio of M+ : M + 2 peak Which element is present? A 122 no M + 2 peak not applicable (Choose one) B 78 80 3:1 (Choose one) C 227 229 1:1 (Choose one)arrow_forwardShow transformation from reactant to product, step by step. *see imagearrow_forward
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