FUNDAMENTALS OF THERMODYNAMICS
10th Edition
ISBN: 9781119634928
Author: Borgnakke
Publisher: WILEY
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A fraction of some power to a motor (1), 2 kW, is turned
into heat transfer at 500 K (2) and then it dissipates in the
ambient at 300 K (3). Give the rates of exergy along the
process 1-2-3.
Water vapor enters a compressor at 100 kPa pressure, 100°C temperature and 1.1 kg/s mass flow rate and exits at 500 kPa pressure and 500°C temperature. Since the heat transfer from the compressor's surface to the environment is 75 kW and the boundary temperature between the compressor and the environment is 100°C,a) Find the exergy of the fluid at the inlet of the compressor (kW).b) Find the exergy of the fluid at the compressor outlet (kW).c) Find the second law efficiency of the compressor.d) Find the exergy destroyed (Exergy extinction) (kW).Note: Changes in kinetic and potential energies will be neglected and T (K) = 273 + °C will be taken. The pressure of the environment is 100 kPa and the temperature is 25°C.
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- 78 kg of water vapor is found as saturated vapor at 650 kPa pressure in a cube-shaped container with a fixed volume. The cube lost heat and its pressure dropped to 325 kPa. Since the environmental conditions are 100 kPa 25 ºC, find the exergy change of the steam in the first and the last state, the exergy change in the steam, the exergy destruction and the second-law efficiency for this process change.arrow_forward1 kg of a fluid expands reversibly according to a linear law from 4.5 bar to 1.6 bar, the initial and final volumes are 0.004 m' and 0.02 m The fluid is then cooled reversibly at C. constant pressure. and finally compressed reversibly according to a law pV back to the initial conditions of 4,5 bar and 0.004 m Determine the work done in each process and the net work of the cycle. Sketch the cycle on a p-v diagram. =constantarrow_forwardNeed ASAP thank you.arrow_forward
- Two reversible cycles are in series, each process doing the same net work, Wcycle. The first cycle receives energy QH by heat transfer from a hot reservoir at 1000°R and energy Q is reinjected by heat transfer to a reservoir at an intermediate temperature, T. The second cycle receives energy Q by heat transfer from the reservoir at temperature T and reinjects the QC energy by heat transfer to the reservoir at a temperature of 400°R. All energy transferred is positive in the direction of the arrow. Determine: a) the intermediate temperature T, in °R, and the thermal efficiency for each of the two cycles; b) the thermal efficiency of a simple reversible cycle operating between the hot and cold reservoirs at 1000°R and 400°C, respectively. Then determine the net work done by the simple cycle, expressed in terms of the net work done by each of the two cycles, Wcycle.arrow_forwardConsider a heat transfer process of the steady form that occurs along a plain wall. While the inner room temperature was kept at 25 °C, the outdoor environment temperature was measured to be 2 °C. If the heat transfer at this plain wall in an hour is 3,528 kJ, determine the.total exergy destruction per unit time (the rate), which occurs during this heat transfer process, a) use the total entropy generation to find the rate of the total exergy destruction in the room (i.e.., use the entropy balance), b) use the exergy balance to find the rate of the total exergy destruction in the roomarrow_forwardHow reversible process differs from irreversible process?arrow_forward
- Air is heated at constant pressure from 2 7 degrees C to 57 degrees C at 3 bar in a heater from an infinite heat source at temperature 227 degrees C Find the gain in availability of air and the effectiveness of the heater. Assume To = 280K and Cp =1.0 kj/kgK.arrow_forwardAn internally reversible process occurs in a system during which Q = – 12 KJ, AU = – 79 KJ and Ah = - 111 KJ A. Find the work if the system is non- flow. B. Determine the work and the change of flow energy if the system is steady state, steady flow system with AEK 4 KJ. %3Darrow_forwardi need the answer quicklyarrow_forward
- Define the Exergy Transfer by Mass, m.arrow_forwardA fluid at 0.6 bar occupying 0.07 m is compressed reversibly to a pressure of 10.2 bar and specific volume of 07 m/kg according to the law pv =c. The fluid then expands reversibly according to the law py =c to 1.9 bar A reversible cooling at constant volume then restores the fluid back to initial state Calculate the net work for the process in Joules.arrow_forwardProvide complete solution and detailed diagram. Find the work needed to isothermally compress 200 m3/min of air from 100 kpa to 700 kpa. A. 294 kw B. 385 kw C. 456 kw D. 649 kwarrow_forward
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