Unit Operations of Chemical Engineering
Unit Operations of Chemical Engineering
7th Edition
ISBN: 9780072848236
Author: Warren McCabe, Julian C. Smith, Peter Harriott
Publisher: McGraw-Hill Companies, The
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Chapter 8, Problem 8.14P

(a)

Interpretation Introduction

Interpretation:

The gas velocity at the centre of the duct for a pitot tube is to be calculated for a particular manometer reading.

Concept Introduction:

Pitot tube is a type of flow meter used to measure the local velocity of the fluid at a particular point. The formula for the velocity of a pitot tube is given as,

  u=pa-pbρ gas ..... (1)

pa − pb = Pressure drop due to manometer

  ρgas = Gas density

The pressure drop due to manometer is,

  pa-pb=ρwgh ..... (2)

The notations used here are,

g = Acceleration due to gravity

h = Manometer reading

  ρw = Density of water

The gas density is given as,

  ρgas=PMRT ..... (3)

P = Pressure of gas

T = Temperature of gas

R = Universal gas constant

M = Molecular weight of the gas

(b)

Interpretation Introduction

Interpretation:

The percent error in the maximum velocity calculated in the previous part is to be determined for changes in dependent parameter.

Concept Introduction:

The error is same for negative and positive sign so we can calculate only for the one sign.

% Error = FinalValue-InitialValueInitialValue×100 ..... (1)

The velocity varies with different factors as,

  uα(ρ)-12.......(2)uα(M)-12.......(3)uα(T)12.......(4)uα(P)12.......(5)

P is the pressure

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chemical engineering Material-energy balance.   Only focus on the nitrogen gas, which is H(3)
1. The settling chamber, shown schematically in Figure 2E1.1, is used as a primary separation device in the removal of dust particles of density 1500 kg/m³ from a gas of density 0:7 kg/m³ and viscosity 1.90 x 10-5 Pa s. Gas inlet Elevation Gas Gas exit exit H Collection surface -W Section X-X Dimensions: H=3m L = 10 m W=2m Figure 2E1.1 Schematic diagram of settling chamber Assuming Stokes' law applies, show that the efficiency of collection of particles of size x is given by the expression collection efficiency, x = x²8(pp - Pi)L 18μHU where U is the uniform gas velocity through the parallel-sided section of the chamber. State any other assumptions made. (b) What is the upper limit of particle size for which Stokes' law applies? (c) When the volumetric flow rate of gas is 0.9 m³/s, and the dimensions of the chamber are those shown in Figure 2E1.1, determine the collection efficiency for spherical particles of diameter 30 mm.
Can you answer this sequantially correct like show me the full process. Also, since it is chemical engineering related problem a perry's handbook is used. Thank you
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Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:9780072848236
Author:Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:McGraw-Hill Companies, The