Database Concepts (7th Edition)
7th Edition
ISBN: 9780133544626
Author: David M. Kroenke, David J. Auer
Publisher: PEARSON
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Expert Solution & Answer
Chapter 8, Problem 8.13RQ
Explanation of Solution
Difference between operational
| Operational database | Dimensional database |
| The data contents get updated in the real-time. Operational database are also called as Online transaction Processing databases. | A relational database that uses dimensional data model in organizing the data is called as dimensional database. |
| Operational database are applied and used for structured transactional processing... |
Expert Solution & Answer
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Students have asked these similar questions
Please run the following program and answer the questions.
#include
int main(void)
{
int arr[6]
=
int *pointer
pointer
*pointer
=
{10, 20, 30, 40, 50, 60};
=
&arr[0];
pointer + 2;
= 5 ;
pointer++;
*pointer
-
(*pointer) 5 ;
pointer++;
*pointer
* (pointer+1)
-
5%;
return 0;
1. [10 pts] Please list the values of elements in array arr after line 8 (*pointer
why.
=
5; ) and explain
>
Comparable
Method
- methodName: String
-priority: int
+ Method()
+ Method(methodName: String, priority: int)
+ abstract specificWay(): void
+ Getters and setters for all fields
compareTo(otherMethod: Method): int
+ toString(): String
ReadMethod
- language: String
+ ReadMethod()
+ ReadMethod(methodName: String,
priority: int, language: String)
+ specificWay(): void
+ Getters and setters for language
+ toString(): String
Part 1.1. Implement the abstract class Method implements Comparable interface according to its UML
diagram. Add comments stating where data fields, constructors, toString(), and other methods are (if
any). Neither method should have an empty body unless abstract methods.
1. two constructors (default and the constructor with all fields)
2. getters and setters for all fields (methodName and priority).
3. toString() method: modify by yourself to match the example output.
4. Abstract method void specificWay().
5. Implement compara To(Method otherMethod) to compare…
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int ll_has_cycle (node *first)
if (first
NULL) return 0;
node *head = first%;B
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head =
head->next;B
return 0;
void test_11_has_cycle() {
int i;
node nodes [6] ;
for (i =
0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value
i;
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
&nodes [3];
nodes [3] .next
nodes [4] .next
& nodes [4];
NULL;
nodes [5] .next
&nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has %s cycle\n\n", 11_has_cycle (&nodes[0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s cycle\n\n",…
Chapter 8 Solutions
Database Concepts (7th Edition)
Ch. 8 - Prob. 8.1RQCh. 8 - Prob. 8.2RQCh. 8 - Prob. 8.3RQCh. 8 - Prob. 8.4RQCh. 8 - Prob. 8.5RQCh. 8 - Prob. 8.6RQCh. 8 - What problems in operational data create the need...Ch. 8 - Prob. 8.8RQCh. 8 - Prob. 8.9RQCh. 8 - Prob. 8.10RQ
Ch. 8 - Explain the difference between a data warehouse...Ch. 8 - Prob. 8.12RQCh. 8 - Prob. 8.13RQCh. 8 - Prob. 8.14RQCh. 8 - Prob. 8.15RQCh. 8 - Prob. 8.16RQCh. 8 - Prob. 8.17RQCh. 8 - Prob. 8.18RQCh. 8 - Prob. 8.19RQCh. 8 - Prob. 8.20RQCh. 8 - Prob. 8.21RQCh. 8 - Prob. 8.22RQCh. 8 - Prob. 8.23RQCh. 8 - Prob. 8.24RQCh. 8 - Prob. 8.25RQCh. 8 - Prob. 8.26RQCh. 8 - Prob. 8.27RQCh. 8 - Explain one way to partition a database that has...Ch. 8 - Prob. 8.29RQCh. 8 - Explain what must be done when fully replicating a...Ch. 8 - Prob. 8.31RQCh. 8 - Prob. 8.32RQCh. 8 - Prob. 8.33RQCh. 8 - Prob. 8.34RQCh. 8 - Explain the meaning of the term object...Ch. 8 - Prob. 8.36RQCh. 8 - Prob. 8.37RQCh. 8 - Prob. 8.38RQCh. 8 - Prob. 8.39RQCh. 8 - Prob. 8.40RQCh. 8 - Prob. 8.41RQCh. 8 - Prob. 8.42RQCh. 8 - Prob. 8.43RQCh. 8 - Prob. 8.44RQCh. 8 - Prob. 8.45RQCh. 8 - Prob. 8.46RQCh. 8 - Prob. 8.47RQ
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