Chapter 8, Problem 8.123QP

Write a balanced equation that predicts the reaction of rubidium (Rb) with (a) H₂O(l), (b) Cl₂(g), (c) H₂(g).

Interpretation Introduction

Interpretation:

The balanced equation reaction between rubidium and water has to be written.

Concept Introduction:

• Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
• Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
• Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
• Balanced chemical equation of a reaction is written according to law of conservation of mass.

Rubidium $\left(Rb\right)$ is an alkali metal with atomic number 37. The electronic configuration of rubidium is $\left[Kr\right]5s^1$

Answer to Problem 8.123QP

The balanced equation reaction between rubidium and water can be given as:

$2R{b}_{\left(s\right)}+2H_2{O}_{\left(l\right)}\underset{}{\to }2{\text{RbOH}}_{\left(aq\right)}+{\text{H}}_{\text{2}}{}_{\left(g\right)}$

Explanation of Solution

Rubidium reacts with water to give $RbOH$ and molecular hydrogen. Reaction can be given as:

$R{b}_{\left(s\right)}+H_2{O}_{\left(l\right)}\underset{}{\to }{\text{RbOH}}_{\left(aq\right)}+{\text{H}}_{\text{2}}{}_{\left(g\right)}$

Here, the number of each element on both sides is made equal by giving the coefficient 2 for the reactant $Rb$ and product $\text{RbOH}$. Also the coefficient 2 is given to ${\text{H}}_{\text{2}}\text{O}$ so that the number of elements on both sides becomes equal.

Therefore,

The balanced equation reaction between rubidium and water can be given as:

$2R{b}_{\left(s\right)}+2H_2{O}_{\left(l\right)}\underset{}{\to }2{\text{RbOH}}_{\left(aq\right)}+{\text{H}}_{\text{2}}{}_{\left(g\right)}$

Interpretation Introduction

Interpretation:

The balanced equation reaction between rubidium and $C{l}_2$ has to be written.

Concept Introduction:

• Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
• Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
• Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
• Balanced chemical equation of a reaction is written according to law of conservation of mass.

Rubidium $\left(Rb\right)$ is an alkali metal with atomic number 37. The electronic configuration of rubidium is $\left[Kr\right]5s^1$

Answer to Problem 8.123QP

The balanced equation reaction between rubidium and $C{l}_2$ can be given as:

$2R{b}_{\left(s\right)}+C{l}_2{}_{\left(g\right)}\underset{}{\to }2\text{Rb}C{l}_{\left(s\right)}$

Explanation of Solution

Rubidium reacts with $C{l}_2$ to give $RbCl$. Reaction can be given as:

$R{b}_{\left(s\right)}+C{l}_2{}_{\left(g\right)}\underset{}{\to }\text{Rb}C{l}_{\left(s\right)}$

Here, the number of each element on both sides is made equal by giving the coefficient 2 for the reactant $Rb$ and product $\text{RbCl}$.

Therefore,

The balanced equation reaction between rubidium and $C{l}_2$ can be given as:

$2R{b}_{\left(s\right)}+C{l}_2{}_{\left(g\right)}\underset{}{\to }2\text{Rb}C{l}_{\left(s\right)}$

Interpretation Introduction

Interpretation:

The balanced equation reaction between rubidium and $H_2$ has to be written.

Concept Introduction:

• Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.
• Reactant of a chemical reaction is the substrate compounds or the compounds which undergo a chemical reaction.
• Product of a chemical reaction is the produced compounds or the compounds formed after a chemical reaction.
• Balanced chemical equation of a reaction is written according to law of conservation of mass.

Rubidium $\left(Rb\right)$ is an alkali metal with atomic number 37. The electronic configuration of rubidium is $\left[Kr\right]5s^1$

Answer to Problem 8.123QP

The balanced equation reaction between rubidium and $H_2$ can be given as:

$2R{b}_{\left(s\right)}+H_2{}_{\left(g\right)}\underset{}{\to }2\text{Rb}{H}_{\left(s\right)}$

Explanation of Solution

Rubidium reacts with $H_2$ to give $RbH$. Reaction can be given as:

$R{b}_{\left(s\right)}+C{l}_2{}_{\left(g\right)}\underset{}{\to }\text{Rb}C{l}_{\left(s\right)}$

Here, the number of each element on both sides is made equal by giving the coefficient 2 for the reactant $Rb$ and product $\text{RbH}$.

Therefore,

The balanced equation reaction between rubidium and $H_2$ can be given as:

$2R{b}_{\left(s\right)}+H_2{}_{\left(g\right)}\underset{}{\to }2\text{Rb}{H}_{\left(s\right)}$