Balanced equation for reaction between potassium hexafluoromanganate(IV) ( K 2 M n F 6 ) and antimony pentafluoride ( SbF 5 ) should be given. Concept Introduction: Chemical equation is the representation of a chemical reaction , in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas. Balanced chemical equation of a reaction is written according to law of conservation of mass. Oxidation: It is the loss of electrons by a species and thus oxidation number is increased. Reduction: It is the gain of electrons by a species and thus oxidation number is decreased An oxidizing agent is a substance that oxidizes another substance in a chemical reaction and itself gets reduced. A reducing agent is a substance that reduces another substance in a chemical reaction and itself gets oxidized.

Question

Want to see the full answer?

Answer 1

Question

Chapter 8, Problem 8.116QP

Interpretation Introduction

Interpretation:

Balanced equation for reaction between potassium hexafluoromanganate(IV) (K2MnF6) and antimony pentafluoride (SbF5) should be given.

Concept Introduction:

Chemical equation is the representation of a chemical reaction, in which the reactants and products of the reactions are represented left and right side of an arrow respectively by using their respective chemical formulas.

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Oxidation: It is the loss of electrons by a species and thus oxidation number is increased.

Reduction: It is the gain of electrons by a species and thus oxidation number is decreased

An oxidizing agent is a substance that oxidizes another substance in a chemical reaction and itself gets reduced.

A reducing agent is a substance that reduces another substance in a chemical reaction and itself gets oxidized.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.

When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol. Which experimental number must be initialled by the Lab TA for the first run of Part 1 of the experiment? a) the heat capacity of the calorimeter b) Mass of sample c) Ti d) The molarity of the HCl e) Tf

Predict products for the Following organic rxn/s by writing the structurels of the correct products. Write above the line provided" your answer D2 ①CH3(CH2) 5 CH3 + D₂ (adequate)" + 2 mited) 19 Spark Spark por every item. 4 CH 3 11 3 CH 3 (CH2) 4 C-H + CH3OH CH2 CH3 + CH3 CH2OH 0 CH3 fou + KMnDy→ C43 + 2 KMn Dy→→ C-OH ") 0 C-OH 1110 (4.) 9+3 =C CH3 + HNO 3 0 + Heat> + CH3 C-OH + Heat CH2CH3 - 3 2 + D Heat H 3 CH 3 CH₂ CH₂ C = CH + 2 H₂ → 2 2