(a) Explanation Given: From 0000 to 9999, a four-digit number is chosen twice a day. Explanation: Consider the experiment of choosing a four-digit number twice a day. As the digits can be repeated in the chosen number, the number of ways of choosing a four-digit number is 10 × 10 × 10 × 10 = 10 , 000 . Since, the number chosen second time in a day is independent of number chosen first time in the day, the number of elements in the sample space will be n ( S ) = 10 , 000 × 10 , 000 = 10 8 Assume that E represents the event that a same number being chosen twice in one day. The number of ways of choosing any four-digit number from 0000 to 9999 first time is 10 × 10 × 10 × 10 = 10 , 000 . The chosen number second time will be same as the number chosen first time, so the number of ways of choosing same four-digit number second time is 1 (b) To determine The probability that the number 3199 being chosen twice in one day.

11th Edition

ISBN: 9780321979438

Author: Margaret L. Lial, Raymond N. Greenwell, Nathan P. Ritchey

Publisher: PEARSON

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Chapter 8, Problem 76RE

(a)

To determine

The probability that same number being chosen twice in one day from 0000 to 9999.

(b)

To determine

The probability that the number 3199 being chosen twice in one day.

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Chapter 8, Problem 75RE

Chapter 8, Problem 77RE

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The probability that same number being chosen twice in one day from 0000 to 9999.

Solution Summary: The author analyzes the probability of a four-digit number being chosen twice in one day from 0000 to 9999.

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The probability that same number being chosen twice in one day from 0000 to 9999.

The probability that the number 3199 being chosen twice in one day.

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