Concept explainers
Consider the raction between N2H4 and N2O4:
A reaction vessel initially contains 27.5g N2H4 and 74.9g of N2O4. Calculate the masses of N2H4, and H2O that will be in reaction vessel after the reactants have reacted as much as possible. Assume 100% yield. Hint: The limiting reactant is completely consumed, but the reactant in excess is not. Use the amount of limiting reactant to determine the amount of products that form and the amount of the reactant in excess that remains after complete reaction.
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- Show work. don't give Ai generated solutionarrow_forwardHi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forwardHi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forward
- . (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. < cleavage Bond A • CH3 + 26. t cleavage 2°C• +3°C• Bond C Cleavage CH3 ZC '2°C. 26. E Strongest 3°C. 2C. Gund Largest BDE weakest bond In that molecule a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest C bond Produces A Weakest Bond Most Strongest Bond Stable radical Strongest Gund produces least stable radicals b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 人 8°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. methyl radical •CH3 formed in bund A Cleavagearrow_forwardWhich carbocation is more stable?arrow_forwardAre the products of the given reaction correct? Why or why not?arrow_forward
- The question below asks why the products shown are NOT the correct products. I asked this already, and the person explained why those are the correct products, as opposed to what we would think should be the correct products. That's the opposite of what the question was asking. Why are they not the correct products? A reaction mechanism for how we arrive at the correct products is requested ("using key intermediates"). In other words, why is HCl added to the terminal alkene rather than the internal alkene?arrow_forwardMy question is whether HI adds to both double bonds, and if it doesn't, why not?arrow_forwardStrain Energy for Alkanes Interaction / Compound kJ/mol kcal/mol H: H eclipsing 4.0 1.0 H: CH3 eclipsing 5.8 1.4 CH3 CH3 eclipsing 11.0 2.6 gauche butane 3.8 0.9 cyclopropane 115 27.5 cyclobutane 110 26.3 cyclopentane 26.0 6.2 cycloheptane 26.2 6.3 cyclooctane 40.5 9.7 (Calculate your answer to the nearest 0.1 energy unit, and be sure to specify units, kJ/mol or kcal/mol. The answer is case sensitive.) H. H Previous Nextarrow_forward
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