Chapter 8, Problem 68E

Interpretation Introduction

Interpretation:

The missing particle is to be drawn and a nuclear equation that represents the given decay is to be written.

Concept Introduction:

In alpha decay, the nucleus emits a particle with mass number 4 and atomic number 2, which is equivalent to a helium nucleus.

In alpha decay, the mass number of the element is reduced by 4 units and the atomic number is decreased by 2 units.