Chapter 8, Problem 65E

Lead ions can be precipitate form solution with $\text{NaCl}$ according to the reaction:

${\text{Pb}}^2\left(aq\right)+2\text{NaCl}\left(aq\right)\to {\text{PbCl}}_2\left(s\right)+2{\text{Na}}^{+}\left(aq\right)$

When 135.8 g $\text{NaCl}$ are added to a solution containing 195.7 g of ${\text{Pb}}^{2+},\text{a}{\text{Pb}}^{2+}$ precipitate forms. The precipitate is filtered dried and found to have a mass of 252.4 g Determine the limiting reactant, theoretical yield of ${\text{PbCl}}_2$, and percent yield for the reaction.