Electric Circuits, Student Value Edition Format: Unbound (saleable)
Electric Circuits, Student Value Edition Format: Unbound (saleable)
11th Edition
ISBN: 9780134747170
Author: NILSSON, James W.^riedel, Susan
Publisher: Prentice Hall
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Chapter 8, Problem 49P
To determine

Find the expression for the voltage vo(t) for t0.

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5. Consider the ac equivalent circuit of an amplifier, where RE = 1 KS2, gm = 0.05 S, and Υπ= 2Κ Ω. (a) Redraw the ac equivalent circuit using the hybrid-pi small signal model for BJTS. Include ro in the model. R₁ ww Vi RB ww + RL Vo RE (b) Find the terminal resistance RIB using the circuit obtained in (a). Ignore ro. Show your work. (Don't use formula for RiB.)
4. Consider the circuit. Use the symbol || to indicate the parallel of resistors in the following questions. (a) Express the input resistance Rin in terms of the terminal resistance and other necessary resistor values. (In other words, RiB, Ric, and RIE are given.) C₁ R₁ R₂ +Vcc Rc C3 R3 C2 ی RE -VEE (b) Express the output resistance Rout in terms of the terminal resistance and other necessary resistor values. (In other words, RiB, Ric and RiE are given.) (c) Express the voltage gain A₁ = ∞ in terms of terminal voltage gain Avt, the terminal Vi resistance, and other necessary resistor values. (Avt, RiB, Ric and R₁E are given.) +51
2. ẞ 100, VBE(on)= 0.7 V, and VCE(sat) = 0.2 V for the BJT. We want to find the Q-point through the following steps. Show your work. a) Find the bias voltage VTH Using Thevenin's equivalent circuit. R1|| R2 www +5 V R₁ = 20 k IB VTH Answer: VTH = V b) Find the base current voltage IB. www. Answer: IB = μA (note the unit.) c) Find the collector voltage Vc (with reference to the ground). RC= 2.3 k B E R₂ = 30 k -5 V www R₁ = 5 ΚΩ ww AHI› RE= 5 ΚΩ

Chapter 8 Solutions

Electric Circuits, Student Value Edition Format: Unbound (saleable)

Ch. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - Prob. 4PCh. 8 - Prob. 5PCh. 8 - Prob. 6PCh. 8 - The natural response for the circuit shown in Fig....Ch. 8 - The natural voltage response of the circuit in...Ch. 8 - The voltage response for the circuit in Fig. 8.1...Ch. 8 - Prob. 10PCh. 8 - Design a parallel RLC circuit (see Fig. 8.1) using...Ch. 8 - Prob. 12PCh. 8 - The initial value of the voltage υ in the circuit...Ch. 8 - Prob. 14PCh. 8 - The resistor in the circuit of Fig. P8.14 is...Ch. 8 - Prob. 16PCh. 8 - The switch in the circuit of Fig. P8.17 has been...Ch. 8 - The inductor in the circuit of Fig. P8.17 is...Ch. 8 - The inductor in the circuit of Fig. P8.17 is...Ch. 8 - Prob. 20PCh. 8 - Prob. 21PCh. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - Prob. 26PCh. 8 - The switch in the circuit in Fig. P8.27 has been...Ch. 8 - For the circuit in Fig. P8.27, find υo for t ≥...Ch. 8 - The switch in the circuit in Fig. P8.29 has been...Ch. 8 - There is no energy stored in the circuit in Fig....Ch. 8 - For the circuit in Fig. P8.30, find υo for t ≥...Ch. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Switches 1 and 2 in the circuit in Fig. P8.35 are...Ch. 8 - The switch in the circuit in Fig. P8.36 has been...Ch. 8 - Prob. 37PCh. 8 - Prob. 38PCh. 8 - In the circuit in Fig. P8.39, the resistor is...Ch. 8 - The initial energy stored in the 50 nF capacitor...Ch. 8 - Prob. 41PCh. 8 - Find the voltage across the 80 nF capacitor for...Ch. 8 - Design a series RLC circuit (see Fig. 8.3) using...Ch. 8 - Change the resistance for the circuit you designed...Ch. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - Prob. 47PCh. 8 - The switch in the circuit shown in Fig. P8.48 has...Ch. 8 - Prob. 49PCh. 8 - The initial energy stored in the circuit in Fig....Ch. 8 - The resistor in the circuit shown in Fig. P8.50 is...Ch. 8 - The resistor in the circuit shown in Fig. P8.50 is...Ch. 8 - The two switches in the circuit seen in Fig. P8.53...Ch. 8 - Prob. 54PCh. 8 - Prob. 55PCh. 8 - The circuit parameters in the circuit of Fig....Ch. 8 - Prob. 57PCh. 8 - Prob. 58PCh. 8 - Prob. 59PCh. 8 - Prob. 60PCh. 8 - Prob. 61PCh. 8 - Derive the differential equation that relates the...Ch. 8 - The voltage signal of Fig. P8.63(a) is applied to...Ch. 8 - The circuit in Fig. P8.63 (b) is modified by...Ch. 8 - Prob. 65PCh. 8 - Prob. 66PCh. 8 - Prob. 67PCh. 8 - Prob. 68P
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