(a)
Interpretation:
For the given organic structures IUPAC name should be identified.
Concept Introduction
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
For
Root word represents the longest continuous carbon skeleton of the organic molecule.
When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
(a)
Answer to Problem 47PP
The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.
Explanation of Solution
To identify: The systematic name for the given structure (a).
Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.
trans-3,4,5,5-tetramethyl-3-heptene
The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.
The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.
The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.
Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.
(b)
Interpretation:
For the given organic structures IUPAC name should be identified.
Concept Introduction
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
For alkenes, suffix will be ‘ene’.
Root word represents the longest continuous carbon skeleton of the organic molecule.
When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
(b)
Answer to Problem 47PP
The systemic name for the molecule (b) is 1-ethylcyclohexene.
Explanation of Solution
To identify: The systematic name for the given structure (b).
Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.
1-ethylcyclohexene
The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.
The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.
Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.
(c)
Interpretation:
For the given organic structures IUPAC name should be identified.
Concept Introduction
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...
For alkenes, suffix will be ‘ene’.
Root word represents the longest continuous carbon skeleton of the organic molecule.
When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.
Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
(c)
Answer to Problem 47PP
The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.
Explanation of Solution
To identify: The systematic name for the given structure (c).
Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.
2–methylbicyclo [2 2 2] oct-2-ene
The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.
The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.
The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.
Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.
The systematic name for the given molecule is given by using the IUPAC rules.
Want to see more full solutions like this?
Chapter 8 Solutions
ORGANIC CHEMISTRY (LL) W/ACCESS
- Which of the given reactions would form meso product? H₂O, H2SO4 III m CH3 CH₂ONa CH3OH || H₂O, H2SO4 CH3 1. LiAlH4, THF 2. H₂O CH3 IVarrow_forwardWhat is the major product of the following reaction? O IV III HCI D = III ა IVarrow_forwardThe reaction of what nucleophile and substrate is represented by the following transition state? CH3 CH3O -Br อ δ CH3 Methanol with 2-bromopropane Methanol with 1-bromopropane Methoxide with 1-bromopropane Methoxide with 2-bromopropanearrow_forward
- What is the stepwise mechanism for this reaction?arrow_forward32. Consider a two-state system in which the low energy level is 300 J mol 1 and the higher energy level is 800 J mol 1, and the temperature is 300 K. Find the population of each level. Hint: Pay attention to your units. A. What is the partition function for this system? B. What are the populations of each level? Now instead, consider a system with energy levels of 0 J mol C. Now what is the partition function? D. And what are the populations of the two levels? E. Finally, repeat the second calculation at 500 K. and 500 J mol 1 at 300 K. F. What do you notice about the populations as you increase the temperature? At what temperature would you expect the states to have equal populations?arrow_forward30. We will derive the forms of the molecular partition functions for atoms and molecules shortly in class, but the partition function that describes the translational and rotational motion of a homonuclear diatomic molecule is given by Itrans (V,T) = = 2πmkBT h² V grot (T) 4π²IKBT h² Where h is Planck's constant and I is molecular moment of inertia. The overall partition function is qmolec Qtrans qrot. Find the energy, enthalpy, entropy, and Helmholtz free energy for the translational and rotational modes of 1 mole of oxygen molecules and 1 mole of iodine molecules at 50 K and at 300 K and with a volume of 1 m³. Here is some useful data: Moment of inertia: I2 I 7.46 x 10- 45 kg m² 2 O2 I 1.91 x 101 -46 kg m²arrow_forward
- K for each reaction step. Be sure to account for all bond-breaking and bond-making steps. HI HaC Drawing Arrows! H3C OCH3 H 4 59°F Mostly sunny H CH3 HO O CH3 'C' CH3 Select to Add Arrows CH3 1 L H&C. OCH3 H H H H Select to Add Arrows Q Search Problem 30 of 20 H. H3C + :0: H CH3 CH3 20 H2C Undo Reset Done DELLarrow_forwardDraw the principal organic product of the following reaction.arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided structures, draw the curved arrows that epict the mechanistic steps for the proton transfer between a hydronium ion and a pi bond. Draw any missing organic structures in the empty boxes. Be sure to account for all lone-pairs and charges as well as bond-breaking and bond-making steps. 2 56°F Mostly cloudy F1 Drawing Arrows > Q Search F2 F3 F4 ▷11 H. H : CI: H + Undo Reset Done DELLarrow_forward
- Calculate the chemical shifts in 13C and 1H NMR for 4-chloropropiophenone ? Write structure and label hydrogens and carbons. Draw out the benzene ring structure when doing itarrow_forward1) Calculate the longest and shortest wavelengths in the Lyman and Paschen series. 2) Calculate the ionization energy of He* and L2+ ions in their ground states. 3) Calculate the kinetic energy of the electron emitted upon irradiation of a H-atom in ground state by a 50-nm radiation.arrow_forwardCalculate the ionization energy of He+ and Li²+ ions in their ground states. Thannnxxxxx sirrr Ahehehehehejh27278283-4;*; shebehebbw $+$;$-;$-28283773838 hahhehdvaarrow_forward
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY