For the given organic structures IUPAC name should be identified . Concept Introduction Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word. Prefix represents the substituent present in the molecule and its position in the root name. Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne , alcohol, carboxylic acid , alcohol etc... For alkenes , suffix will be ‘ ene ’. Root word represents the longest continuous carbon skeleton of the organic molecule. When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo , if it is two cyclic structure combined then prefixed with bicyclo . Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer . If the bulky groups are in opposite side then it is trans-isomer .

Question

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Answer 1

Question

Chapter 8, Problem 47PP

(a)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(a)

Expert Solution

Answer to Problem 47PP

The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.

Explanation of Solution

To identify: The systematic name for the given structure (a).

Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 1

trans-3,4,5,5-tetramethyl-3-heptene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.

The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.

The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.

Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.

(b)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(b)

Expert Solution

Answer to Problem 47PP

The systemic name for the molecule (b) is 1-ethylcyclohexene.

Explanation of Solution

To identify: The systematic name for the given structure (b).

Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 2

1-ethylcyclohexene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.

The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.

Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.

(c)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(c)

Expert Solution

Answer to Problem 47PP

The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.

Explanation of Solution

To identify: The systematic name for the given structure (c).

Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 3

2–methylbicyclo [2 2 2] oct-2-ene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.

The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.

The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.

Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.

Conclusion

The systematic name for the given molecule is given by using the IUPAC rules.

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Answer 2

Question

Chapter 8, Problem 47PP

(a)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(a)

Expert Solution

Answer to Problem 47PP

The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.

Explanation of Solution

To identify: The systematic name for the given structure (a).

Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 1

trans-3,4,5,5-tetramethyl-3-heptene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.

The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.

The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.

Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.

(b)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(b)

Expert Solution

Answer to Problem 47PP

The systemic name for the molecule (b) is 1-ethylcyclohexene.

Explanation of Solution

To identify: The systematic name for the given structure (b).

Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 2

1-ethylcyclohexene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.

The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.

Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.

(c)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(c)

Expert Solution

Answer to Problem 47PP

The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.

Explanation of Solution

To identify: The systematic name for the given structure (c).

Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 3

2–methylbicyclo [2 2 2] oct-2-ene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.

The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.

The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.

Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.

Conclusion

The systematic name for the given molecule is given by using the IUPAC rules.

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Answer 3

Question

Chapter 8, Problem 47PP

(a)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(a)

Expert Solution

Answer to Problem 47PP

The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.

Explanation of Solution

To identify: The systematic name for the given structure (a).

Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 1

trans-3,4,5,5-tetramethyl-3-heptene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.

The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.

The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.

Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.

(b)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(b)

Expert Solution

Answer to Problem 47PP

The systemic name for the molecule (b) is 1-ethylcyclohexene.

Explanation of Solution

To identify: The systematic name for the given structure (b).

Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 2

1-ethylcyclohexene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.

The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.

Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.

(c)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(c)

Expert Solution

Answer to Problem 47PP

The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.

Explanation of Solution

To identify: The systematic name for the given structure (c).

Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 3

2–methylbicyclo [2 2 2] oct-2-ene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.

The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.

The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.

Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.

Conclusion

The systematic name for the given molecule is given by using the IUPAC rules.

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Answer 4

Question

Chapter 8, Problem 47PP

(a)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(a)

Expert Solution

Answer to Problem 47PP

The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.

Explanation of Solution

To identify: The systematic name for the given structure (a).

Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 1

trans-3,4,5,5-tetramethyl-3-heptene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.

The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.

The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.

Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.

(b)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(b)

Expert Solution

Answer to Problem 47PP

The systemic name for the molecule (b) is 1-ethylcyclohexene.

Explanation of Solution

To identify: The systematic name for the given structure (b).

Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 2

1-ethylcyclohexene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.

The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.

Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.

(c)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(c)

Expert Solution

Answer to Problem 47PP

The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.

Explanation of Solution

To identify: The systematic name for the given structure (c).

Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 3

2–methylbicyclo [2 2 2] oct-2-ene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.

The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.

The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.

Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.

Conclusion

The systematic name for the given molecule is given by using the IUPAC rules.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 8, Problem 47PP

(a)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(a)

Expert Solution

Answer to Problem 47PP

The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.

Explanation of Solution

To identify: The systematic name for the given structure (a).

Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 1

trans-3,4,5,5-tetramethyl-3-heptene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.

The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.

The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.

Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.

(b)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(b)

Expert Solution

Answer to Problem 47PP

The systemic name for the molecule (b) is 1-ethylcyclohexene.

Explanation of Solution

To identify: The systematic name for the given structure (b).

Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 2

1-ethylcyclohexene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.

The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.

Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.

(c)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(c)

Expert Solution

Answer to Problem 47PP

The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.

Explanation of Solution

To identify: The systematic name for the given structure (c).

Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 3

2–methylbicyclo [2 2 2] oct-2-ene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.

The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.

The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.

Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.

Conclusion

The systematic name for the given molecule is given by using the IUPAC rules.

Answer 6

Chapter 8, Problem 47PP

(a)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(a)

Expert Solution

Answer to Problem 47PP

The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.

Explanation of Solution

To identify: The systematic name for the given structure (a).

Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 1

trans-3,4,5,5-tetramethyl-3-heptene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.

The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.

The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.

Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.

Answer 7

Chapter 8, Problem 47PP

(a)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

Answer 8

(a)

Expert Solution

Answer to Problem 47PP

The systematic name for the molecule (a) is trans-3,4,5,5-tetramethyl-3-heptene.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

To identify: The systematic name for the given structure (a).

Draw the given molecule (a) and find the longest parent carbon chain or carbon skeleton and the substituents for naming the compound.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 1

trans-3,4,5,5-tetramethyl-3-heptene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is the chain which contains 7 carbons. Hence the root name of the molecule is hept. Since it is an alkene with 7 carbons then heptene will be the parent carbon chain name.

The substituents present in the molecule are methyl groups on 3, 4 and 5. Therefore on numbering the three methyl groups are present at 3, 4 and 5, 5 positions is 3, 4, 5, 5-tetramethyl.

The bulky groups attached on the opposite sides of double bonded carbon atoms, so the given alkene molecule is ‘trans’.

Hence the systematic name for the molecule (a) is trans-3, 4, 5, 5-tetramethyl-3-heptene.

Answer 13

(b)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(b)

Expert Solution

Answer to Problem 47PP

The systemic name for the molecule (b) is 1-ethylcyclohexene.

Explanation of Solution

To identify: The systematic name for the given structure (b).

Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 2

1-ethylcyclohexene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.

The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.

Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.

Answer 14

(b)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

Answer 15

(b)

Expert Solution

Answer to Problem 47PP

The systemic name for the molecule (b) is 1-ethylcyclohexene.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

To identify: The systematic name for the given structure (b).

Draw the given molecule (b) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 2

1-ethylcyclohexene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is cyclic in nature which consists of 6 carbons so the root word for the molecule is cyclohexane. The suffix ‘ene’ is used since it is an alkene.

The substituent present in the molecule are 1 ethyl group. Therefore it named as 1-ethyl in suffix.

Hence the systematic name for the molecule (b) is 1-ethylcyclohexene.

Answer 20

(c)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

(c)

Expert Solution

Answer to Problem 47PP

The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.

Explanation of Solution

To identify: The systematic name for the given structure (c).

Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 3

2–methylbicyclo [2 2 2] oct-2-ene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.

The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.

The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.

Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.

Conclusion

The systematic name for the given molecule is given by using the IUPAC rules.

Answer 21

(c)

Interpretation Introduction

Interpretation:

For the given organic structures IUPAC name should be identified.

Concept Introduction

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc...

For alkenes, suffix will be ‘ene’.

Root word represents the longest continuous carbon skeleton of the organic molecule.

When a molecule consists of cyclic structure, the root word of the molecule is prefixed with cyclo, if it is two cyclic structure combined then prefixed with bicyclo.

Two stereoisomers are there for an alkene molecule. It depends upon the location of bulky group (or high molecular weight) on the double bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.

Answer 22

(c)

Expert Solution

Answer to Problem 47PP

The systematic name for molecule (c) is 2–methyl bicyclo [2 2 2] oct-2-ene.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

To identify: The systematic name for the given structure (c).

Draw the given molecule (d) and find the longest parent carbon chain or carbon skeleton and the substituents.

ORGANIC CHEM PRINT STUDY GDE & SSM, Chapter 8, Problem 47PP , additional homework tip 3

2–methylbicyclo [2 2 2] oct-2-ene

The given molecule is drawn. The parent carbon skeleton is the longest continuous carbon chain that should contain more number of carbons. In the given molecule the parent carbon skeleton is bicyclic in nature which consists of 8 carbons so the root word for the molecule is bicyclooctane. The suffix ‘ene’ is used since it is an alkene.

The given molecule is bicyclo fused alkene, number of carbons at the bridge and bridge head is counted and it is found that there are 2 carbons each at bridge head and 2 carbons at bridge.

The substituents present in the molecule are 1 methyl group. Therefore it named as 1-methyl in suffix.

Hence the systematic name for the molecule (c) is 2–methylbicyclo [2 2 2] oct-2-ene.