Chapter 8, Problem 46P

Determine the value of the force P which will cause motion of the 25-kg block to impend up the 34° incline. The cylinder is fixed to the block and does not rotate. The coefficients of static friction are ₁ = 0.22 and ₂ = 0.38. H1 25 kg H₂ O 34° 24°

The two 200-N blocks are pushed apart by the 15 degrees wedge of negligible weight. The angle of static friction is 10 degrees at all contact surfaces. Determine the force P required to start the blocks moving.

Determine the coefficient of static friction between the friction pad at A and ground if the inclination of the ladder is 0 =60° and the wall at B is smooth when the 82-kg man climbs up the leader and stops at the position shown after he senses that the leader is on the verge of slipping. The center of gravity for the man is at G. Neglect the weight of the leader.

The man pushes on the roller with force P through a handle that connects to the central axle of the roller. If the coefficient of static friction between the 49-lb roller and the floor is s = 0.22, determine the maximum force Pthat can be applied to the handle, so that roller rolls on the ground without slipping. Assume the roller to be a uniform cylinder. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper unit. Take g = 32.2 ft/s2. 1.5 ft 30° Your Answer: Answer units

333

3 - please show the complete solution, thanks!

Determine the smallest horizontal force P required to lift the 100-kg cylinder. The coefficient of static friction at the contact points A and B are 0.6 and 0.2, respectively. The coefficient of static friction between the wedge and the ground is 0.3.

The man pushes on the roller with force P through a handle that connects to the central axle of the roller. If the coefficient of static friction between the 43-lb roller and the floor is g = 0.16, determine the maximum force P that can be applied to the handle, so that roller rolls on the ground without slipping. Assume the roller to be a uniform cylinder. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper unit. Take g = 32.2 ft/s². Your Answer: Answer 30° units 1.5 ft

4. The mine car and its contents have a total mass of 6000 kg and a centre of gravity at G. If the coefficient of static friction 10 kN between the wheels and the 0.9 m •G tracks is u = 0.4 when the wheels are locked, find the normal force acting on the front wheels at B and the rear 0.15 m 0.6 m - 1.5 m wheels at A when the brakes at both A and B are locked. Does the car move? [Ans. NA = 16.5 kN, Ng =42.3 kN, the car does not move] %3D lyp