EBK MATLAB: AN INTRODUCTION WITH APPLIC
6th Edition
ISBN: 8220103113663
Author: GILAT
Publisher: YUZU
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Textbook Question
Chapter 8, Problem 3P
Determine the polynomial y(x) that has roots at x = -0.7, x=0.5, x=3.4, and x=5.8. Make a plot of the polynomial in the domain
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2-1) Lathi & Ding prob. 2.5-2 For the signals y(t) and x(t) shown below, find the component of the form
y(t) contained in x(t). In other words, find the optimum value of c in the approximation x(t) = cy(t) so that
the error signal energy is minimum. Also compute the error signal energy.
y(t)
x(t)
0
1
0
1
1. Is1 = 2ls2 = 4 × 10-16 A, B₁ = ẞ2 = 100, and R₁ = 5 kQ. Find the VB such that lx = 1 mA.
(30 points)
R1
ww
Q2
+
VB
Figure 1
2-2) Lathi & Ding prob. 2.6-1
2.6-1 Find the correlation coefficient p between of signal x(t) and each of the four pulses g1(1), 82(1),
83(1), and g4(f) shown in Fig. P2.6-1. To provide maximum margin against the noise along the
transmission path, which pair of pulses would you select for a binary communication?
Figure P.2.6-1
x(f)
(a)
8(1)
(b)
82(1)
(c)
1
1
sin 2πt
sin 4πt
-sin 2
0
0.707
83(1)
0
1
(d)
0
M
P
0.707
84(1)
(e)
0
0.5
-0.707
Chapter 8 Solutions
EBK MATLAB: AN INTRODUCTION WITH APPLIC
Ch. 8 - Prob. 1PCh. 8 - Plot the polynomial y=0.7x413.5x2+6x37 in the...Ch. 8 - Determine the polynomial y(x) that has roots at x...Ch. 8 - Use MATLAB to carry out the following...Ch. 8 - Use MATLAB to carry out the following...Ch. 8 - Use MATLAB to divide the polynomial...Ch. 8 - Use MATLAB to divide the ploynomial...Ch. 8 - The product of four consecutive even integers is...Ch. 8 - The product of three integers with spacing of 3...Ch. 8 - The product of three distinct integers is 6240....
Ch. 8 - A rectangular steel container (no top) has the...Ch. 8 - An aluminum container has the geometry shown in...Ch. 8 - A rectangular box (no top) is welded together...Ch. 8 - The probability P of selecting three distinct...Ch. 8 - Write a user-defined function that adds or...Ch. 8 - Write a user-defined function that multiplies two...Ch. 8 - Write a user-defined function that calculates the...Ch. 8 - A cylinder with base radius rand height h is...Ch. 8 - Consider the parabola: x = 2(y-2)2 +3,and the...Ch. 8 - The following data is given: x -5 -4 -1 1 4 6 9 10...Ch. 8 - 21. The boiling temperature of water TB at various...Ch. 8 - The U.S. population in selected years between 1815...Ch. 8 - The number of bacteria NBmeasured at different...Ch. 8 - Growth data of a sunflower plant is given tn the...Ch. 8 - Use the growth data from Problem 24 for the...Ch. 8 - 26. The following points are given: x 1 2.2 3.7...Ch. 8 - The standard air density. D (average of...Ch. 8 - Write a user-defined function that determines the...Ch. 8 - Estimated values of thermal conductivity of...Ch. 8 - Measurements of the concentration, C, of a...Ch. 8 - Use the data from Problem 30 for the following:...Ch. 8 - The relationship between two variables y and x is...Ch. 8 - Curve-lit the data from the previous problem with...Ch. 8 - When rubber is stretched, its elongation is...Ch. 8 - The transmission of light through a transparent...
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- Crystallographic planes Crystallographic planes are denoted by Miller indices. 5b Algorithm for Miller indices 1. Read off intercepts of plane with axes in terms of a, b, c 2. Take reciprocals of intercepts 3. Reduce to smallest integer values 4. Enclose in parentheses, no commas. 353 1/3 1/5 1/3 535 (535) In the cubic system, a plane and a direction with the same indices are orthogonal. E.g. [100] direction is perpendicular to (100) plane. Correspondingly, [123] direction is perpendicular to (123) plane. [2,3,3] Plane intercepts axes at 3a, 2b, 2c 2 11 1 Reciprocal numbers are: 3'2'2 b. Indices of the plane (Miller): (2,3,3) 2 a Indices of the direction: [2,3,3] X (200) (100) (110) (111) (100) Indices of crystallographic plane can be found from cross product of indices of any two non-parallel directions in this plane.arrow_forwardCrystallographic positions Crystallographic position is denoted by three numbers, which are coefficients of the position vector, e.g. ½½½ for the red atom. Here the 'new' atom is at a/2 + b/2 + c/2 Silicon crystal has so-called "diamond type lattice". Each Si atom has 4 nearest neighbors. Diamond lattice starts with a FCC lattice and then adds four additional INTERNAL atoms at locations r = a/4+b/4+c/4 away from each of the atoms. In other words, diamond lattice is formed by two FCC lattices sifted by the vector r.arrow_forwardfind the answers for this prelabarrow_forward
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