Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 8, Problem 3P

To determine

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Expert Solution & Answer

Answer to Problem 3P

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Explanation of Solution

Given:

Incomplete table

mv	Mv	d(pc)	p (arc second)
-	7	10	-
11	-	1000	-
-	-2	-	0.025
4	-	-	0.040

Formula used:

Distance of star in parsec is calculated as

d(pc)=1p(arc seconds)

Absolute magnitude of the star is given as

HORIZONS (LL) W/WEBASSIGN ACCESS CARD, Chapter 8, Problem 3P

Calculation:

Parallax of star is calculated as

10=1p(arc seconds)p=0.1

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−7=−5+5log10(10)mv=7

Parallax of star is calculated as

1000=1p(arc seconds)p=0.001

Absolute magnitude of the star is calculated as

mv−Mv=−5+5log10(d)11−Mv=−5+5log10(1000)Mv=1

Distance of star is calculated as

d=10.025p=400 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−(−2)=−5+5log10(400)mv=6.0

Distance of star is calculated as

d=10.040p=250 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)4−Mv=−5+5log10(250)Mv=−2.98

Therefore the complete table is as follows

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Conclusion:

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

If an object that has a mass of 2m and moves with velocity v to the right collides with another mass of 1m that is moving with velocity v to the left, in which direction will the combined inelastic collision move?

Please solve this question

Please solve

Answer 2

Question

Chapter 8, Problem 3P

To determine

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Expert Solution & Answer

Answer to Problem 3P

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Explanation of Solution

Given:

Incomplete table

mv	Mv	d(pc)	p (arc second)
-	7	10	-
11	-	1000	-
-	-2	-	0.025
4	-	-	0.040

Formula used:

Distance of star in parsec is calculated as

d(pc)=1p(arc seconds)

Absolute magnitude of the star is given as

HORIZONS (LL) W/WEBASSIGN ACCESS CARD, Chapter 8, Problem 3P

Calculation:

Parallax of star is calculated as

10=1p(arc seconds)p=0.1

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−7=−5+5log10(10)mv=7

Parallax of star is calculated as

1000=1p(arc seconds)p=0.001

Absolute magnitude of the star is calculated as

mv−Mv=−5+5log10(d)11−Mv=−5+5log10(1000)Mv=1

Distance of star is calculated as

d=10.025p=400 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−(−2)=−5+5log10(400)mv=6.0

Distance of star is calculated as

d=10.040p=250 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)4−Mv=−5+5log10(250)Mv=−2.98

Therefore the complete table is as follows

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Conclusion:

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 8, Problem 3P

To determine

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Expert Solution & Answer

Answer to Problem 3P

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Explanation of Solution

Given:

Incomplete table

mv	Mv	d(pc)	p (arc second)
-	7	10	-
11	-	1000	-
-	-2	-	0.025
4	-	-	0.040

Formula used:

Distance of star in parsec is calculated as

d(pc)=1p(arc seconds)

Absolute magnitude of the star is given as

HORIZONS (LL) W/WEBASSIGN ACCESS CARD, Chapter 8, Problem 3P

Calculation:

Parallax of star is calculated as

10=1p(arc seconds)p=0.1

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−7=−5+5log10(10)mv=7

Parallax of star is calculated as

1000=1p(arc seconds)p=0.001

Absolute magnitude of the star is calculated as

mv−Mv=−5+5log10(d)11−Mv=−5+5log10(1000)Mv=1

Distance of star is calculated as

d=10.025p=400 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−(−2)=−5+5log10(400)mv=6.0

Distance of star is calculated as

d=10.040p=250 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)4−Mv=−5+5log10(250)Mv=−2.98

Therefore the complete table is as follows

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Conclusion:

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 8, Problem 3P

To determine

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Expert Solution & Answer

Answer to Problem 3P

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Explanation of Solution

Given:

Incomplete table

mv	Mv	d(pc)	p (arc second)
-	7	10	-
11	-	1000	-
-	-2	-	0.025
4	-	-	0.040

Formula used:

Distance of star in parsec is calculated as

d(pc)=1p(arc seconds)

Absolute magnitude of the star is given as

HORIZONS (LL) W/WEBASSIGN ACCESS CARD, Chapter 8, Problem 3P

Calculation:

Parallax of star is calculated as

10=1p(arc seconds)p=0.1

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−7=−5+5log10(10)mv=7

Parallax of star is calculated as

1000=1p(arc seconds)p=0.001

Absolute magnitude of the star is calculated as

mv−Mv=−5+5log10(d)11−Mv=−5+5log10(1000)Mv=1

Distance of star is calculated as

d=10.025p=400 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−(−2)=−5+5log10(400)mv=6.0

Distance of star is calculated as

d=10.040p=250 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)4−Mv=−5+5log10(250)Mv=−2.98

Therefore the complete table is as follows

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Conclusion:

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 8, Problem 3P

To determine

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Expert Solution & Answer

Answer to Problem 3P

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Explanation of Solution

Given:

Incomplete table

mv	Mv	d(pc)	p (arc second)
-	7	10	-
11	-	1000	-
-	-2	-	0.025
4	-	-	0.040

Formula used:

Distance of star in parsec is calculated as

d(pc)=1p(arc seconds)

Absolute magnitude of the star is given as

HORIZONS (LL) W/WEBASSIGN ACCESS CARD, Chapter 8, Problem 3P

Calculation:

Parallax of star is calculated as

10=1p(arc seconds)p=0.1

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−7=−5+5log10(10)mv=7

Parallax of star is calculated as

1000=1p(arc seconds)p=0.001

Absolute magnitude of the star is calculated as

mv−Mv=−5+5log10(d)11−Mv=−5+5log10(1000)Mv=1

Distance of star is calculated as

d=10.025p=400 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−(−2)=−5+5log10(400)mv=6.0

Distance of star is calculated as

d=10.040p=250 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)4−Mv=−5+5log10(250)Mv=−2.98

Therefore the complete table is as follows

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Conclusion:

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Answer 6

Chapter 8, Problem 3P

To determine

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Expert Solution & Answer

Answer to Problem 3P

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Explanation of Solution

Given:

Incomplete table

mv	Mv	d(pc)	p (arc second)
-	7	10	-
11	-	1000	-
-	-2	-	0.025
4	-	-	0.040

Formula used:

Distance of star in parsec is calculated as

d(pc)=1p(arc seconds)

Absolute magnitude of the star is given as

HORIZONS (LL) W/WEBASSIGN ACCESS CARD, Chapter 8, Problem 3P

Calculation:

Parallax of star is calculated as

10=1p(arc seconds)p=0.1

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−7=−5+5log10(10)mv=7

Parallax of star is calculated as

1000=1p(arc seconds)p=0.001

Absolute magnitude of the star is calculated as

mv−Mv=−5+5log10(d)11−Mv=−5+5log10(1000)Mv=1

Distance of star is calculated as

d=10.025p=400 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−(−2)=−5+5log10(400)mv=6.0

Distance of star is calculated as

d=10.040p=250 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)4−Mv=−5+5log10(250)Mv=−2.98

Therefore the complete table is as follows

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Conclusion:

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Answer 7

Chapter 8, Problem 3P

To determine

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Answer 8

Expert Solution & Answer

Answer to Problem 3P

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given:

Incomplete table

mv	Mv	d(pc)	p (arc second)
-	7	10	-
11	-	1000	-
-	-2	-	0.025
4	-	-	0.040

Formula used:

Distance of star in parsec is calculated as

d(pc)=1p(arc seconds)

Absolute magnitude of the star is given as

HORIZONS (LL) W/WEBASSIGN ACCESS CARD, Chapter 8, Problem 3P

Calculation:

Parallax of star is calculated as

10=1p(arc seconds)p=0.1

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−7=−5+5log10(10)mv=7

Parallax of star is calculated as

1000=1p(arc seconds)p=0.001

Absolute magnitude of the star is calculated as

mv−Mv=−5+5log10(d)11−Mv=−5+5log10(1000)Mv=1

Distance of star is calculated as

d=10.025p=400 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)mv−(−2)=−5+5log10(400)mv=6.0

Distance of star is calculated as

d=10.040p=250 pc

Apparent magnitude of the star is calculated as

mv−Mv=−5+5log10(d)4−Mv=−5+5log10(250)Mv=−2.98

Therefore the complete table is as follows

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Conclusion:

Complete table is as follows-

mv	Mv	d(pc)	p (arc second)
7	7	10	0.1
11	1	1000	0.001
6	-2	400	0.025
4	-2.98	250	0.040

Answer 12

Ch. 8 - Prob. 1RQ Ch. 8 - Why was the Hipparcos satellite able to make more...Ch. 8 - Prob. 3RQ Ch. 8 - Prob. 4RQ Ch. 8 - Prob. 5RQ Ch. 8 - Prob. 6RQ Ch. 8 - Prob. 7RQ Ch. 8 - Prob. 8RQ Ch. 8 - Prob. 9RQ Ch. 8 - Prob. 10RQ

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Concept explainers

Complete the table of apparent magnitude, absolute visual magnitude, distances, and parallaxes.

Answer to Problem 3P

Explanation of Solution

Want to see more full solutions like this?

Chapter 8 Solutions