Explanation Given Information: The matrix A is, A = [ 1 − 1 − 2 3 ] Formula used: A − 1 = 1 det A adj ( A ) Calculation: At first we will find, det A = 3 ( 1 ) − 1 ( 2 ) = 3 − 2 = 1 The inverse of the matrix A is calculated as below: A − 1 = 1 det A [ 3 1 2 1 ] = 1 1 [ 3 1 2 1 ] = [ 3 1 2 1 ] Now we will consider, A A − 1 = [ 1 − 1 − 2 3 ] [ 3 1 2 1 ] = [ 1 ( 3 ) − 1 ( 2 ) 1 ( 1 ) − 1 ( 1 ) − 2 ( 3 ) + 3 ( 2 ) − 2 ( 1 ) + 3 ( 1 )

6th Edition

ISBN: 9780134469140

Author: Robert F. Blitzer

Publisher: PEARSON

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Chapter 8, Problem 39RE

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To calculate: The A−1 for the matrix A=[1−1−23].

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Chapter 8, Problem 38RE

Chapter 8, Problem 40RE

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Chapter 8 Solutions

Precalculus (6th Edition)

Ch. 8.1 - Check Point 1 Write the augmented matrix for the...Ch. 8.1 - Check Point 2 Use the matrix ...Ch. 8.1 - Check Point 3 Use matrices to solve the system:...Ch. 8.1 - Check Point 4 Use matrices to solve the system:...Ch. 8.1 - Check Point 5 Solve the system in Check Point. 3...Ch. 8.1 - Prob. 1CVC Ch. 8.1 - Fill in each blank so that the resulting statement...Ch. 8.1 - Prob. 3CVC Ch. 8.1 - Prob. 4CVC Ch. 8.1 - Fill in each blank so that the resulting statement...

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The A − 1 for the matrix A = [ 1 − 1 − 2 3 ] .

Solution Summary: The author explains that the inverse of the matrix A is, A-1=left[cc1& 1 -2& 3end

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To calculate: The A−1 for the matrix A=[1−1−23].

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Chapter 8 Solutions