Explanation Given Information: The system of equations x − 2 y + z = 2 2 x − y − z = 1 Calculation: Consider the given system of equations x − 2 y + z = 2 2 x − y − z = 1 Therefore, the system of equation can be expressed as below: [ 1 − 2 1 2 − 1 − 1 ] [ x y z ] = [ 2 1 ] Consider, z = t , t ∈ ℝ . So, [ 1 − 2 2 − 1 ] [ x y ] + t [ 1 − 1 ] = [ 2 1 ] [ 1 − 2 2 − 1 ] [ x y ] = [ 2 1 ] − t [ 1 − 1 ] [ 1 − 2 2 − 1 ] [ x y ] = [ 2 − t 1 + t ] Therefore, this system can be expressed as A X = B Where A = [ 1 − 2 2 − 1 ] , B = [ 2 − t 1 + t ] , X = [ x y ] Therefore, the solution of the equation is given by: X = A − 1 B Consider the determinant of the matrix is | A | =</

6th Edition

ISBN: 9780134469140

Author: Robert F. Blitzer

Publisher: PEARSON

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Chapter 8, Problem 2T

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To calculate: The solution of system of equation x−2y+z=2 and 2x−y−z=1

using matrix method.

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The solution of system of equation x − 2 y + z = 2 and 2 x − y − z = 1 using matrix method.

Solution Summary: The author calculates the solution of system of equations x-2y+z=2 and 2x-y=1 using matrix method.

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To calculate: The solution of system of equation x−2y+z=2 and 2x−y−z=1

using matrix method.

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Chapter 8 Solutions

The solution of system of equation x − 2 y + z = 2 and 2 x − y − z = 1 using matrix method.

Solution Summary: The author calculates the solution of system of equations x-2y+z=2 and 2x-y=1 using matrix method.

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To calculate: The solution of system of equation x−2y+z=2 and 2x−y−z=1 using matrix method.

Want to see the full answer?

Chapter 8 Solutions

To calculate: The solution of system of equation x−2y+z=2 and 2x−y−z=1

using matrix method.