Chapter 8, Problem 39QAP

The beam ABC has a mass of 79.0 kg and is supported by the rope BDC that runs through the frictionless pulley at D . The winch at C has a mass of 36.5 kg. The tension in the rope acts on the beam at points B and C and counteracts the moments due to the beam's weight (acting vertically at the midpoint of its length) and the weight of the winch (acting vertically at point C) such that the resultant moment about point A is equal to zero. Assume that rope segment CD is vertical and note that rope segment BD is NOT necessarily perpendicular to the beam. a.) Compute the tension in the rope. b.) Model the two forces the rope exerts on the beam as a single equivalent force and couple moment acting at point B. Enter your answer in Cartesian components. c.) Model the two forces the rope exerts on the beam as a single equivalent force (no couple) and determine the distance from A to the point along the beam where the equivalent force acts (measured parallel to the beam from A ). Enter your answer…

w1 Three distributed loads act on a beam as shown. The load between A and B increases linearly from 0 to a maximum intensity of w₁ = 12.8 lb/ft at point B. The load then varies linearly with a different slope to an intensity of w₂ = 17.1 lb/ft at C. The load intensity in section CD of the beam is constant at w3 10.2 lb/ft. For each load region, determine the resultant force and the location of its line of action (distance to the right of A for all cases). cc 10 BY NC SA 2016 Eric Davishahl = WI W2 W3 -b- C Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 4.50 ft b 5.85 ft с 4.28 ft The resultant load in region AB is FR₁ = lb and acts ft to the right of A. The resultant load in region BC is FR2 lb and acts = ft to the right of A. The resultant load in region CD is FR3 = lb and acts ft to the right of A.

The T-shaped structure is embedded in a concrete wall at A and subjected to the force F₁ and the force-couple system F2 1650 N and M = 1,800 N-m at the locations shown. Neglect the weight of the structure in your calculations for this problem. = a.) Compute the allowable range of magnitudes for F₁ in the direction shown if the connection at A will fail when subjected to a resultant moment with a magnitude of 920 N- m or higher. b.) Focusing on the forces and igonoring given M for now. Using the value for F1, min that you calculated in (a), replace the two forces F₁ and F2 with a single force that has equivalent effect on the structure. Specify the equivalent →> force Feq in Cartesian components and indicate the horizontal distance from point A to its line of action (note this line of action may not intersect the structure). c.) Now, model the entire force system (F1,min, F2, and M) as a single force and couple acting at the junction of the horizontal and vertical sections of the…