Explanation Given: f ( x ) = 2 x 2 − 4 x − 6 = 2 ( x − 1 ) 2 − 8 Graph: Here, f ( x ) = 2 ( x − 1 ) 2 − 8 . Comparing the equation with a ( x − h ) 2 + k = 0 , we have a = 2, h = 1 and k = -8 As a > 0, so parabola open upwards. h = 1 and k = -8; so, vertex is (1, -8)

8th Edition

ISBN: 9780136553632

Author: Blitzer

Publisher: VST

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Chapter 8, Problem 36RE

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To graph: The quadratic equation f(x)=2x2−4x−6 using vertex and intercepts.

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Chapter 8, Problem 35RE

Chapter 8, Problem 37RE

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Chapter 8 Solutions

EBK INTERMEDIATE ALGEBRA FOR COLLEGE ST

Ch. 8.1 - Check Point 1 Solve: . Ch. 8.1 - Prob. 2CP Ch. 8.1 - Prob. 3CP Ch. 8.1 - Prob. 4CP Ch. 8.1 - Prob. 5CP Ch. 8.1 - Prob. 6CP Ch. 8.1 - Prob. 7CP Ch. 8.1 - Prob. 8CP Ch. 8.1 - Prob. 9CP Ch. 8.1 - Prob. 10CP

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To graph: The quadratic equation f ( x ) = 2 x 2 − 4 x − 6 using vertex and intercepts.

Solution Summary: The author illustrates the quadratic equation f(x)=2x 2-4x-6 using vertex and intercepts.

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To graph: The quadratic equation f(x)=2x2−4x−6 using vertex and intercepts.

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Chapter 8 Solutions